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Siven : dy ax + 3xy ty² x² + xy 3xy ty X2 txy 2 у dy бус х xt = 0

Siven : dy ax + 3xy ty² x² + xy 3xy ty X2 txy 2 у dy бус х xt = 0

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Given: dy + 3xy ty = 0 xy => day бус х - (3xy + y²) xy Fax (371) =>dx (-3 xy + y²) = dy (-X² - xy) →dx (-3 x (x) ³²+ (ux)² = (udx+xdv) (-x²-x²²² (Ux)) => -3 x² u dx + ²x² dx = -x² udx - x² v² dx - x³ du- x³dv (+x²udx) (²x) (+ x² udx) (+ x² u²dx) => - [ 2x²udx + 2√³x²dx = -x ³du -x³udu => 2x²xdx = 2√³²x²dx = X du txodu x3 => 2x²dx-2ux² dx => (2x² = x²) dx = 2 f 1 d X = In x y = x; dy= udx + xdu dx = f == du Đinx nu c In u => e = e => X = UC 2 du du + du du J-²1 =)/x = C 1 Zu y=vx
Transcribed Image Text:Given: dy + 3xy ty = 0 xy => day бус х - (3xy + y²) xy Fax (371) =>dx (-3 xy + y²) = dy (-X² - xy) →dx (-3 x (x) ³²+ (ux)² = (udx+xdv) (-x²-x²²² (Ux)) => -3 x² u dx + ²x² dx = -x² udx - x² v² dx - x³ du- x³dv (+x²udx) (²x) (+ x² udx) (+ x² u²dx) => - [ 2x²udx + 2√³x²dx = -x ³du -x³udu => 2x²xdx = 2√³²x²dx = X du txodu x3 => 2x²dx-2ux² dx => (2x² = x²) dx = 2 f 1 d X = In x y = x; dy= udx + xdu dx = f == du Đinx nu c In u => e = e => X = UC 2 du du + du du J-²1 =)/x = C 1 Zu y=vx
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