SITUATION. The basic data for proportioning trial batches for normal weight concrete with an average with an compressive strength of 35 MPa at 28 days are as follows: Slump = 75 mm to 100 mm Water- cement ratio by weight = 0.48 Specific gravity of cement = 3.15 Specific gravity of coarse aggregate 2.68 Specific gravity of fine aggregate = 2.64 Water (net mixing) = 180 kg / m^3 Concrete unit weight = 23.6 kN/m^3 What is the approximate combined weight (kN) of water, cement, coarse aggregate, if the volume of dry rodded coarse aggregate is 0.38m^3/m^3? 13.5 15.5 19.9 21.8
SITUATION. The basic data for proportioning trial batches for normal weight concrete with an average with an compressive strength of 35 MPa at 28 days are as follows: Slump = 75 mm to 100 mm Water- cement ratio by weight = 0.48 Specific gravity of cement = 3.15 Specific gravity of coarse aggregate 2.68 Specific gravity of fine aggregate = 2.64 Water (net mixing) = 180 kg / m^3 Concrete unit weight = 23.6 kN/m^3 What is the approximate combined weight (kN) of water, cement, coarse aggregate, if the volume of dry rodded coarse aggregate is 0.38m^3/m^3? 13.5 15.5 19.9 21.8
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
G
![SITUATION.
The basic data for proportioning trial batches for normal weight concrete with an average with
an compressive strength of 35 MPa at 28 days are as follows:
Slump = 75 mm to 100 mm
Water- cement ratio by weight 0.48
Specific gravity of cement = 3.15
Specific gravity of coarse aggregate = 2.68
Specific gravity of fine aggregate = 2.64
Water (net mixing) = 180 kg / m^3
Concrete unit weight = 23.6 kN/m^3
What is the approximate combined weight (kN) of water, cement, coarse aggregate, if the
volume of dry rodded coarse aggregate is 0.38m^3/m^3?
13.5
15.5
19.9
21.8](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe688a216-e0ed-4ec3-97d3-a6314f31cb8a%2Ffa412bf3-86eb-4840-b7e2-6545ae619a05%2Fwya9ci_processed.jpeg&w=3840&q=75)
Transcribed Image Text:SITUATION.
The basic data for proportioning trial batches for normal weight concrete with an average with
an compressive strength of 35 MPa at 28 days are as follows:
Slump = 75 mm to 100 mm
Water- cement ratio by weight 0.48
Specific gravity of cement = 3.15
Specific gravity of coarse aggregate = 2.68
Specific gravity of fine aggregate = 2.64
Water (net mixing) = 180 kg / m^3
Concrete unit weight = 23.6 kN/m^3
What is the approximate combined weight (kN) of water, cement, coarse aggregate, if the
volume of dry rodded coarse aggregate is 0.38m^3/m^3?
13.5
15.5
19.9
21.8
![(continuation)
How many m^3 of entrapped air present for every m^3 concrete mixture?
0.01
0.1
0.015
0.001
(continuation)
If the combined solid volume of cement, water, coarse aggregate and entrapped air is 0.65
m^3 what weight (kN) of dry sand is required?
15.9
13.0
11.6
9.1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe688a216-e0ed-4ec3-97d3-a6314f31cb8a%2Ffa412bf3-86eb-4840-b7e2-6545ae619a05%2Fomqkdlm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(continuation)
How many m^3 of entrapped air present for every m^3 concrete mixture?
0.01
0.1
0.015
0.001
(continuation)
If the combined solid volume of cement, water, coarse aggregate and entrapped air is 0.65
m^3 what weight (kN) of dry sand is required?
15.9
13.0
11.6
9.1
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