Q2 SITUATION. A fully continuous monolithic floor system consists of slab as shown. Use the ACImoment coefficient as provided by the code.-M (interior support)= -+M (midspan) =16740003.40003.40003.00003.0000Design data:Live load= 4 kPaFloor finish= 1 kPaCeiling load= 0.25 kPafc'= 21 MPafy= 276 MPaUse 12 mm diameter as main reinforcement.Use 10 mm diameter as secondary reinforcement.Compute the spacing of the main bars at the support.210 mm220 mm450 mm300 mm

In general, the spacing between two bars in a beam depends on the maximum aggregate size used in the…

SITUATION. A fully continuous monolithic floor system consists of slab as shown. Use the ACI moment coefficient as provided by the code. -M (interior support)= 12 1 +M (midspan) = 16 %3D 74000 3.4000 3.4000 30000 3.0000

SITUATION. A fully continuous monolithic floor system consists of slab as shown. Use the ACI moment coefficient as provided by the code. -M (interior support)= 12 1 +M (midspan) = 16 %3D 74000 3.4000 3.4000 30000 3.0000

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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An alloy is an admixture of two or more metals or a metal and a non-metal. Since ancient times, man has been using alloys. Alloying helps to retain the properties of the parent matter, such as hardness, strength, toughness, ductility and is corrosion-resistant. Copper alloys such as brass have antimicrobial properties that help to fight against (Coronavirus disease 2019) COVID-19 and other hospital-acquired infections. Some common alloys are brass, bronze, solder steel, etc. Most alloys have a lower melting point than their constituents. This is due to the presence of a nonmetal as one of the constituents that behaves as an impurity and restricts the raise of melting point.

Question

SITUATION. A fully continuous monolithic floor system consists of slab as shown. Use the ACI
moment coefficient as provided by the code.
-M (interior support)= -
+M (midspan) =
16
74000
3.4000
3.4000
3.0000
3.0000
Design data:
Live load= 4 kPa
Floor finish= 1 kPa
Ceiling load= 0.25 kPa
fc'= 21 MPa
fy= 276 MPa
Use 12 mm diameter as main reinforcement.
Use 10 mm diameter as secondary reinforcement.
Compute the spacing of the main bars at the support.
210 mm
220 mm
450 mm
300 mm

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