SITUATION: A square footing carries an allowable axial load of 1000KN kg with its bottom resting on a ground water table at a depth of 1.5 m below the ground surface. (Nc = 35, Nq = 22, Ny = 19). Take PDRY = 17 kN/m3 and PSAT = 20.5 kN/m3, C = 10kPa kg/m2. Compute the ultimate bearing capacity of the soil 1143.11 Determine the dimension of the footing using a factor of safety of 3. O 1.62 3255.21 0.96 1248.70 1.55 1670.75 1.34 O O

SITUATION: A square footing carries an allowable axial load of 1000KN kg with its bottom resting on a ground water table at a depth of 1.5 m below the ground surface. (Nc = 35, Nq = 22, Ny = 19). Take PDRY = 17 kN/m3 and PSAT = 20.5 kN/m3, C = 10kPa kg/m2. Compute the ultimate bearing capacity of the soil 1143.11 Determine the dimension of the footing using a factor of safety of 3. O 1.62 3255.21 0.96 1248.70 1.55 1670.75 1.34 O O

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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). A circular footing 3 m in diameter is shown below. 6. [Soil Bearing Capacity] (* Assume the general shear failure and use a factor of safety 2.8. Determine the follow N. = 25. 13 , Nq = 12.72, N, = 8.34 a. The gross allowable bearing capacity. b. Net Allowable bearing capacity c. The safe load that the footing can carry. Ground surface Y= 18.5 kN/m? C = 80 kPa = 25° 1.1 m D,- 1.8 m Water table Ye = 19.2 kN/m? Diameter = 3m
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A footing 4 mx 2 m in a plan, transmits a pressure of 150kN/m² on a cohesive soil have E = 6 x 10¹kN/m² and × μ = 0.5. What will be the immediate settlement of the footing at the center? Take influence factor = 1.5
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A medium dense soil has the following properties: cohesion = 6 kPaγsoil = 14.7 kN/m3 Φ=22o. Factor of safety = 2.5If a circular footing is 2 meters deep from the ground surface, with a diameter of 2.2 meters, what is the net allowable load (kN) that the footing can carry. Choices: A. 280.59 kNB. 896.78 kNC. 410.47 kND. 2690.34 kN
15 The soil arrangement shown carries 1.88-meter square footing with a column load of 596 kN. Properties of sand: Above water table = 17.04 kN/m3, Below water table = 18.19 kN/m3. Properties of clay: 17.10 kN/m3, Cc = 0.383, void ratio = 0.65. Use H1 = 6 m., H2 = 7 m., H3 = 5 m., Df = 1 m. Determine the settlement of the normally consolidated clay in mm. Round off to three decimal places.
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FDE 006. The square footing shown carries a load of 3500 KN. Assume that the stress below the footing is distributed at a slope 1H:2V. The clay layer is overconsolidated with OCR=2. Q = 3500kN Vd 17.5kN/m'. Sand- Vsat 18.3kN/m³ Ysat 17.1kN/m² eo=1.4 Refer to FDE 006. Determi the settlement of the overconsolidated clay layer. Select the correct response: 101.819 mm 73.624 mm 37.561 mm 86.241 mm Clay 3m x 3m GWT Cs= 0.06 Cc = 0.38 0.6m 0.6m 1.2m 1.2m