Situation 3: A line 100m long was paced by a surveyor five times with the following data: 152, 153.5, 154.5, 152.25 and 155. Then another line was paced five times again and the surveyor yielded with the following results: 860, 863.25, 861.75, 862.5 and 863. 8. Determine the pace factor. 1.535 m/pace b. 0.652 m/pace c. 0. 562 m/pace d. 1. 545 m/pace a. e. NOTC 9. Determine the mean number of paces for the new line. c. 861.20 paces d. 861.02 paces 862.01 paces b 862.10 paces a. e. NOTC 10. Determine the distance of the new line. 484.450 m b. 484.502 m C. 562.098 m d. 562.089 m e. NOTC 11. If the tape distance of the new line is 561.5m, solve for the relative precision. -0.001049 -0.0001049 C. -0.01049 d. -0.001409 a. e. NOTC b.

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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Solve this fundamentals of surveying question.
Situation 3:
A line 100m long was paced by a surveyor five times with the following data: 152, 153.5,
154.5, 152.25 and 155. Then another line was paced five times again and the surveyor yielded
with the following results: 860, 863.25, 861.75, 862.5 and 863.
8. Determine the pace factor.
1.535 m/pace
b. 0.652 m/pace
c. 0. 562 m/pace
d. 1. 545 m/pace
a.
e. NOTC
9. Determine the mean number of paces for the new line.
c. 861.20 paces
d. 861.02 paces
862.01 paces
b 862.10 paces
a.
e. NOTC
10. Determine the distance of the new line.
484.450 m
b.
484.502 m
C. 562.098 m
d. 562.089 m
a.
e. NOTC
11. If the tape distance of the new line is 561.5m, solve for the relative precision.
- 0.001049
-0 0001049
C. -0.01049
d. -0.001409
a.
e. NOTC
Transcribed Image Text:Situation 3: A line 100m long was paced by a surveyor five times with the following data: 152, 153.5, 154.5, 152.25 and 155. Then another line was paced five times again and the surveyor yielded with the following results: 860, 863.25, 861.75, 862.5 and 863. 8. Determine the pace factor. 1.535 m/pace b. 0.652 m/pace c. 0. 562 m/pace d. 1. 545 m/pace a. e. NOTC 9. Determine the mean number of paces for the new line. c. 861.20 paces d. 861.02 paces 862.01 paces b 862.10 paces a. e. NOTC 10. Determine the distance of the new line. 484.450 m b. 484.502 m C. 562.098 m d. 562.089 m a. e. NOTC 11. If the tape distance of the new line is 561.5m, solve for the relative precision. - 0.001049 -0 0001049 C. -0.01049 d. -0.001409 a. e. NOTC
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