Situation 1. The force P = 75 lb is applied normal to the plane of the uniform panel door that weighs 50 lb and is prevented from opening by the strut C, which is a light two-force member whose upper end is secured under the door knob and whose lower end is attached to a rubber cup which does not slip on the floor. Of the door hinges A and B, only B can support force in the vertical z-direction. 6. Calculate the force in strut C. a. 150.120 lb 40 c. 100.240 Ib d. 200.200 Ib b. 125.100 lb 7. Determine the total (resultant) reaction force exerted by the hinge at A on the panel door a. 84.552 Ib c. 63.638 Ib 40" b. 99.106 Ib d. 71.140 Ib 8. Determine the total (resultant) reaction force exerted by the hinge at B on the panel door. a. 154.368 Ib b. 98.904 Ib c. 103.403 Ib c. 245.250 N 30

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Situation 1. The force P = 75 lb is applied normal to the plane of the
uniform panel door that weighs 50 lb and is prevented
from opening by the strut C, which is a light two-force
member whose upper end is secured under the door
knob and whose lower end is attached to a rubber cup
which does not slip on the floor. Of the door hinges A
and B, only B can support force in the vertical z-direction.
6. Calculate the force in strut C.
a. 150.120 lb
P.
48
40"
c. 100.240 lb
b. 125.100 Ib
d. 200.200 lb
7. Determine the total (resultant) reaction force exerted by
the hinge at A on the panel door
a. 84.552 Ib
c. 63.638 Ib
40"
b. 99.106 Ib
d. 71.140 Ib
8. Determine the total (resultant) reaction force exerted by
the hinge at B on the panel door.
a. 154.368 Ib
c. 103.403 Ib
c. 245.250 N
30"
b. 98.904 lb
Transcribed Image Text:Situation 1. The force P = 75 lb is applied normal to the plane of the uniform panel door that weighs 50 lb and is prevented from opening by the strut C, which is a light two-force member whose upper end is secured under the door knob and whose lower end is attached to a rubber cup which does not slip on the floor. Of the door hinges A and B, only B can support force in the vertical z-direction. 6. Calculate the force in strut C. a. 150.120 lb P. 48 40" c. 100.240 lb b. 125.100 Ib d. 200.200 lb 7. Determine the total (resultant) reaction force exerted by the hinge at A on the panel door a. 84.552 Ib c. 63.638 Ib 40" b. 99.106 Ib d. 71.140 Ib 8. Determine the total (resultant) reaction force exerted by the hinge at B on the panel door. a. 154.368 Ib c. 103.403 Ib c. 245.250 N 30" b. 98.904 lb
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