[sin(x)cos(2x)sin(3x) dx sin(3x)cos(3x) sin(2x); [cos(2x) – 1]+ +C + 12 8 4 sin(3x)cos(3x) sin(2x)cos(2x) sin(2x) + 12 8 8 sin(6x) sin(2x) sin(2x)cos(2x) 24 8 8 +C 4 sin(6x) sin(2x) sin(2x)cos(4x) X +-+C

Q: •2 1 -dx- J-3 (x + 7)(x² + 16)

A: Given integral is Apply partial fractions to break the denominator

Q: Find where z = sin (x²) cos (y) COS © 6.x sin (x²) cos (y²) COS 2.x sin (2²) 2x cos 2.x sin (x²) cos…

A:

Q: [ 2x sin (4x)dx O =cos (4x) + C -x² 4 2 sin (4x) + 8x cos (4x) + C sin (4x) – x cos (4x) + C ○중cos…

A: Integration by parts

Q: dx x4+16 Įtan-( x2 + c 4

A: Given that, ∫xx4+16dx

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A: This we directly computed by the rule of integration that is there is no any dificulty to find the…

Q: Evaluate cos (x (x2 – 2x + 1) (2x - 2) sin (x 2 - 2x +1) (2 – 2x) sin (x? – 2x + 1) O (2x 2) cos (x-…

A:

Q: J sin(x)cos(2x)sin(3x) dx sin(3x)cos(3x) , sin(2x)cos(2x) , sin(2x) + + C 12 8 8 4 sin(6x)_ sin(2x)…

A: