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sin(x) X-0 x = 1 by computing values close to 0. Use this fact with 1-cos(x) x the conjugation method, and the Limit Laws, to prove that lim X-0 (Hint: Multiply the top and bottom by 1 + cos (x). Nice stuff happens) In the previous section, we found that lim <=0

sin(x) X-0 x = 1 by computing values close to 0. Use this fact with 1-cos(x) x the conjugation method, and the Limit Laws, to prove that lim X-0 (Hint: Multiply the top and bottom by 1 + cos (x). Nice stuff happens) In the previous section, we found that lim <=0

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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sin(x) X-0 X 2. In the previous section, we found that lim = 1 by computing values close to 0. Use this fact with = 0 1-cos(x) x the conjugation method, and the Limit Laws, to prove that lim X-0 (Hint: Multiply the top and bottom by 1 + cos (x). Nice stuff happens)
Transcribed Image Text:sin(x) X-0 X 2. In the previous section, we found that lim = 1 by computing values close to 0. Use this fact with = 0 1-cos(x) x the conjugation method, and the Limit Laws, to prove that lim X-0 (Hint: Multiply the top and bottom by 1 + cos (x). Nice stuff happens)
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