sinx= sin2 (a) Region #1: Bounded by y sin r and y sin 2.r on the interval [0. 7] CoSx =} sinx=2sinxcOsx 6-2sincosx-sina Per= 2 O=sintrzcosk-I de (sinx- sinz) dx y = sin x (sin2x-sinx)dx y = sin 21 (snzx-sin) dx + "(snx-sin2x)dx Area Integral: (set-up only)

Q: What is the derivative of y= 3Arcsin xº, 3 Arcsin x In 3 A y' = 1 - xa 3 Arcsin x* In 3 3 B y' : (а…

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Q: tan"x jun's de - | tan"-x dx (n 1) n- 1 tan x sec" r sec x dx (n 1) n- 1

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Q: integral by part x² dx

A: Given that  The integral is

Q: Q3\ Evaluate only TWO integrals A-ſ tan5 (x)sec*(x)dx P ( sin(x)+esin (x)+sex³ (x) B-S sec (x)…

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Q: Consider the function f(x) whose second derivative is f"(x)=5x+3sinx if f(0)=2 and f'(0)=2 what is…

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Q: s sin² (3x) cos³ (3x) dx Hint: cos²x = 1 - sin² x 07 sin²x = 1 - cos² x

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Q: S tan5 x dx O 1/4 sec^2 x(sec^2 x - 1) - In Icosx |+ C 1/4 (sec^4 x - sec^2 x -In Icosx |)+ C O 1/4…

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Q: S (sin'x-sinx-x' sin* x+x²sin x) dx ? :-x° sin* x + x² sin x) dx ? What is the value of the…

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Q: d) cosec ² (x) dy = sec (4) dx -cos (2x) Ssin²(x) dx = -1/2/1-Cos(2x) dx -1/2 (X-1/2 Sin(2x))+C dy…

A: The given differential equation is;  Csc2(x) dy=sec(y)dx.

Q: S(csc x cot x + 7x°)dx sec x + x'+c csc x + x' +c - sec x + x' +c - sin x + x' + c csc x + x' +c

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Q: 2xdx – [3y* +(x² - y' )tan y] = 0

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Q: tan 0+ tan* 0 = sec* 0 - sec? 0 %3D

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Q: Evaluate Jin (5x)/x dx * O In^2 (5x) + C O (1/2) In 2 (5x) + C (1/5) In^2 (5x) + c O (1/2) In^2 (5x)…

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Q: what are the inflection point relationship of stationary point and critical point  what are the…

A: What are inflection points? Relationship of stationary point and critical point  What are the…

Q: Solve the equation (2xy - tan y)dx + (x^2 - x (sec y)^2))dy = 0

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Q: Using integral table

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Q: Use Chain rule find the derivative w= 4x^2 +3y^2 with respect to t along the path x=sint and y= cost…

A: Note: “Since you have asked multiple question, we will solve the first question for for you. To get…