sin(x) Find the Maclaurin series of x8 Σ n=0

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Title: Finding the Maclaurin Series of \(\frac{\sin(x)}{x^8}\)

---

**Problem Statement:**

Find the Maclaurin series of \(\frac{\sin(x)}{x^8}\).

**Expression Format:**

\[
\sum_{n=0}^{\infty} \boxed{\phantom{element}}
\]

This problem requires finding the Maclaurin series (a type of Taylor series centered at 0) for the function given by \(\frac{\sin(x)}{x^8}\).

**Approach:**

1. Recall the Maclaurin series for \(\sin(x)\), which is given by:
   \[
   \sin(x) = \sum_{n=0}^{\infty} \frac{(-1)^n x^{2n+1}}{(2n+1)!}
   \]

2. Substitute this series expression into \(\frac{\sin(x)}{x^8}\).

3. Simplify the series by dividing each term by \(x^8\).

4. The resulting series will provide the desired Maclaurin series for the given function.

This process involves basic operations such as series manipulation and algebraic simplification.
Transcribed Image Text:Title: Finding the Maclaurin Series of \(\frac{\sin(x)}{x^8}\) --- **Problem Statement:** Find the Maclaurin series of \(\frac{\sin(x)}{x^8}\). **Expression Format:** \[ \sum_{n=0}^{\infty} \boxed{\phantom{element}} \] This problem requires finding the Maclaurin series (a type of Taylor series centered at 0) for the function given by \(\frac{\sin(x)}{x^8}\). **Approach:** 1. Recall the Maclaurin series for \(\sin(x)\), which is given by: \[ \sin(x) = \sum_{n=0}^{\infty} \frac{(-1)^n x^{2n+1}}{(2n+1)!} \] 2. Substitute this series expression into \(\frac{\sin(x)}{x^8}\). 3. Simplify the series by dividing each term by \(x^8\). 4. The resulting series will provide the desired Maclaurin series for the given function. This process involves basic operations such as series manipulation and algebraic simplification.
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