sin?n n (in n (In h = 2

Q: 1 En=1 4n² 8n +3

A: ∑n=1+∞ 14n2-8n+3using limit comparison testlimn→∞ 14n2-8n+31n2limn→∞ n24n2-8n+3factorisinglimn→∞…

Q: Find the converges or diverges.

A: Here I attached the detailed explanation to the questionExplanation:Solution:

Q: 2. 8[][

A: The objective of the question is checking the convergence or divergence of the given series.

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A:

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A:

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A:

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A:

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A:

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A:

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A:

Q: comparison test L=1 n¯ +n + 1 3 n° – 5 -

A: The series is divergent by Comparison test.   The details solution is as follows below:

Q: 1 3 .5 4 X +x

A:

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A:

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A:

Q: sin² x -dx converges 8.

A: We will use comparison theorem here

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A: # we are entitled to solve one question at time, please resubmit the other if you wish to get it…

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A:

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A:

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A:

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A: Topic :- Integration If the limit exists as a real number, then the simple improper integral is…

Q: 1 n + 1 n = 4 /- 8.

A:

Q: 8 (-9) n n10n+1

A: given series Find: convergence or divergence of the series

Q: +00 Inn E(-1)": n2 n=2

A: Solution