sinh(3-j5) (3 + j4)4 13-j7 (3 – j5)(2-j7)

Q: tanx V3+ts

A: According to the Leibniz rule, we have: ddx∫u(x)v(x)f(t)dt=f(v(x))·ddx[v(x)]-f(u(x))·ddx[u(x)]

Q: Jg+X -J9-X

A: We are given 0/0 form so we find limit by rationalize the given function

Q: (a) Solution: Try u = x + y. Then This is separable Thence 1 du dx u² = x² + C 1+ dy dx dy dx = =…

A: Student is not able to understand few steps in the solution so I just have to add these steps.

Q: 2+(29-xy)

A: We first get rid of the bracket.  So,  2+(29-xy)=2+29-xy

Q: 2y-(4y+3)>6y+3(y+4)

A:

Q: 8(a+9) =

A: Given,           8(a + 9)

Q: 6. Convert your pair of complex numbers to polar form.

A:

Q: 2(3q-9)=9-3q

A:

Q: Expand and simplify: (9z - 2z+ 10)(3z + 12)

A:

Q: Simplify= (3x+z)(2x+y)= (3x+z)(2x)+(3x+2)(y)

A: It is given that,3x+z2x+y=3x+z2x+3x+zy. We have to simplify it.

Q: 7(3x+6)=11-(x+2)

A: Given an algebraic equation. We shall solve the equation for x.

Q: 2(x+7)^2-2=6

A: Given expression is,

Q: (q/q-3) + 1 = (2/2q+1)

A: To solve for q, firstly, we take l.c.m on left hand side of equation.

Q: 9(a + b) = 9a+

A: Given, 9(a + b) = 9a+

Q: 2x³+1 Evaluate / 7+x-6 dx

A:

Q: 2x-x xp - (r-1)° (x²+1) -0-

A: Given ∫-∞0 2x-x3x-12x2+1 dx                         =-∫-∞0x3-2xx-12x2+1dx…

Q: 2. -8p(p -3 - 10p) 5. (6a - 3b)(-2a) 3. m'(m + 2n - 6) 6. -3x(2x - 3)

A: We multiply each follow 2nd step.

Q: c. 2+ = 3 с.

A:

Q: (24+2x-x2)1/2dx

A:

Q: 8(c-3d)-(3c+d)

A: The given expression is

Q: 8/(x+1) - 3/2 = 4/(3x+3) What is x?

A:

Q: g³ + x² + 2x+1 d.x (x² + 1)(x² + 2)

A: Explanation of the answer is as follows

Q: (8t/t-4)+(3/4-t)

A: Given:

Q: Sxex² dx O 2+x²²/²/2/ HI HIN 6 1 2 HIN ex²+ + C + C + C

A:

Q: x² – (4 + 3) 9(x) = 5 Find q ^-1 (2)

A: qx=x2-4+35⇒qx=x2-75 Let qx=y⇒x=q-1y               1 x2-75=y⇒x2-7=y-5⇒x2-7=y-52⇒x=7+y-52

Q: Exercise 4. Evaluate f* (3VE+)dz (4A) 6 (4B) 7 (4C) 18 (4D) 10 (4E) 17

A:

Q: 6 ³ / ( 2 / +72+4) dz x6 Find + C

A: We need to calculate the value of integral∫6x6+7x+4dx