음(sinh-1(x)) = EXAMPLE 4 Prove that + x2 SOLUTION Let y = sinh-(x). Then sinh(y) = x. If we differentiate this equation implicitly with respect to x, we get dy dx = 1. Since cosh?(y) - sinh?(y) = 1 and cosh(y) 2 0, we have cosh(y) = V1 + sinh?(y), so 1. dy dx 1 cosh(y) V1+ sinh?(y)
음(sinh-1(x)) = EXAMPLE 4 Prove that + x2 SOLUTION Let y = sinh-(x). Then sinh(y) = x. If we differentiate this equation implicitly with respect to x, we get dy dx = 1. Since cosh?(y) - sinh?(y) = 1 and cosh(y) 2 0, we have cosh(y) = V1 + sinh?(y), so 1. dy dx 1 cosh(y) V1+ sinh?(y)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![음(sinh-1(x)) =
EXAMPLE 4 Prove that
+ x2
SOLUTION Let y = sinh-(x). Then sinh(y) = x. If we differentiate this equation implicitly with respect to x, we get
dy
dx
= 1.
Since cosh?(y) - sinh?(y) = 1 and cosh(y) 2 0, we have cosh(y) = V1 + sinh?(y), so
1.
dy
dx
1
cosh(y)
V1+ sinh?(y)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F030351ce-7395-4d65-a8bf-32d9b407aff1%2Fa89e6872-f930-4750-94a6-ebc644cf0ba1%2Fgh1mz0e_processed.png&w=3840&q=75)
Transcribed Image Text:음(sinh-1(x)) =
EXAMPLE 4 Prove that
+ x2
SOLUTION Let y = sinh-(x). Then sinh(y) = x. If we differentiate this equation implicitly with respect to x, we get
dy
dx
= 1.
Since cosh?(y) - sinh?(y) = 1 and cosh(y) 2 0, we have cosh(y) = V1 + sinh?(y), so
1.
dy
dx
1
cosh(y)
V1+ sinh?(y)
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