Since the aluminum bar is not an isolated system, the second law of thermodynamics cannot be applied to the bar alone. Rather, it should be applied to the bar in combination with its surroundings (the lake). Assume that the entropy change of the bar is -1238 J/K. What is the change in total entropy A.Stotal? Express your answer numerically in joules per Kelvin ▸ View Available Hint(s) AStotal = ΜΕ ΑΣΦ ? J/K ! You have already submitted this answer. Enter a new answer. No credit lost. Try again.

Since the aluminum bar is not an isolated system, the second law of thermodynamics cannot be applied to the bar alone. Rather, it should be applied to the bar in combination with its surroundings (the lake). Assume that the entropy change of the bar is -1238 J/K. What is the change in total entropy A.Stotal? Express your answer numerically in joules per Kelvin ▸ View Available Hint(s) AStotal = ΜΕ ΑΣΦ ? J/K ! You have already submitted this answer. Enter a new answer. No credit lost. Try again.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Subject: Statistical and Thermal Physics Only number 3. Please supply all the equation and solutions needed to solve for this set of problem. Thank you.
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