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Since f'(c) f(1) – (0) f(1) – f(0) = 1, f(c) = 1. We therefore equate f'(x) to 1 and solve for x. and %3! %3D 1-0 1-0 f'(x) = 1 4-1/5 = 1 x-1/5 4. Raise both sides of the equation to the fifth power and simplify. 15.

Since f'(c) f(1) – (0) f(1) – f(0) = 1, f(c) = 1. We therefore equate f'(x) to 1 and solve for x. and %3! %3D 1-0 1-0 f'(x) = 1 4-1/5 = 1 x-1/5 4. Raise both sides of the equation to the fifth power and simplify. 15.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Since f'(c) f(1) – (0) (1) - f(0) = 1, f(c) = 1. We therefore equate f'(x) to 1 and solve for x. and %3D %3D 1-0 1-0 f'(x) = 1 4-1/5 = 1 x-1/5 4. Raise both sides of the equation to the fifth power and simplify.
Transcribed Image Text:Since f'(c) f(1) – (0) (1) - f(0) = 1, f(c) = 1. We therefore equate f'(x) to 1 and solve for x. and %3D %3D 1-0 1-0 f'(x) = 1 4-1/5 = 1 x-1/5 4. Raise both sides of the equation to the fifth power and simplify.
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