sin(82) Set 02 = 90° in Snell's Law and solve for 0, to determine the critical angle of incidence at which total internal reflection begins to occur when light passes from glass to air. (Note that the index of refraction from glass to air is the reciprocal of the index from air to glass. Round your answer to one decimal place.) Refraction from air to substance Substance Water 1.33 Alcohol 1.36 Glass 1.52 Diamond 241

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter25: Reflection And Refraction Of Light
Section: Chapter Questions
Problem 7OQ: Light traveling in a medium of index of refraction n1 is incident on another medium having an index...
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When light passes from a more-dense to a less-dense medium-from glass to air, for example-the angle of refraction predicted by Snell's Law can be 90° or larger. In this case the light beam is actually reflected
back into the denser medium. This phenomenon, called total internal reflection, is the principle behind fiber optics. Snell's Law is given below.
sin(01)
V1
sin(02)
V2
Set 0, = 90° in Snell's Law and solve for 0, to determine the critical angle of incidence at which total internal reflection begins to occur when light passes from glass to air. (Note that the index of refraction from
glass to air is the reciprocal of the index from air to glass. Round your answer to one decimal place.)
01 =
Refraction
from air
to substance
Substance
Water
1.33
Alcohol
1.36
Glass
1.52
Diamond
2.41
Transcribed Image Text:When light passes from a more-dense to a less-dense medium-from glass to air, for example-the angle of refraction predicted by Snell's Law can be 90° or larger. In this case the light beam is actually reflected back into the denser medium. This phenomenon, called total internal reflection, is the principle behind fiber optics. Snell's Law is given below. sin(01) V1 sin(02) V2 Set 0, = 90° in Snell's Law and solve for 0, to determine the critical angle of incidence at which total internal reflection begins to occur when light passes from glass to air. (Note that the index of refraction from glass to air is the reciprocal of the index from air to glass. Round your answer to one decimal place.) 01 = Refraction from air to substance Substance Water 1.33 Alcohol 1.36 Glass 1.52 Diamond 2.41
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