sin(-x)+ cos(-x) = − sin x + cos x

Q: If f(x) =sin x sin2x sin3x find f" (x)

A: Given f(x) and find second derivative of this function. We use trigonometry relations and derivative…

Q: 2 cos^2 x-sin x -1=0

A: 2cos2x-sinx-1=0⇒1-sinx-2sin2x=0⇒sinx=-1, sinx=12⇒x=3π2+2πn, x=π6+2πn, x=5π6+2πn

Q: If f(x) = 7 sin-(*), then f'(2) - =

A: dsin-1xdx = 11-x2 dxndx=n.xn-1

Q: Prove the following trigonometric identities. 1 cotx a) 6 cosx| 6 cosx = 6sin² x COSX CSCX

A: The details solution is given below

Q: (sin-'(cos(2x) + cos-'(sin(2x).

A: Given : ddxsin-1cos2x+cos-1sin2x

Q: if Sec X = 2 then tanx +Cos X =

A:

Q: cos(-x)+sin(x=x) Q4 prove that sinx 2

A:

Q: cos(4x) cos(2x) sin(4x) sec(2x) 12. Verify: - sin(2x)

A: cos(2x ) =cos2(x)-sin2(x) = 2cos2(x)-1 =1-2sin2(x) sin(2x) = 2sin(x) cos(x)

Q: cos2x

A:

Q: 1-cosx sinx

A: Using Trigonometry property,

Q: 1 + csc x  / cos x + cot x

A: Given information:

Q: Sin (플-) sec(-x) =

A: To solve sin[(π/2)-x] sec(-x)

Q: tan-1 (tanx)= x where..............

A: It is known that tan-1tanx=x for all values lies on -π2, π2.

Q: ·/₁ Evaluate cos x sin³ x dx. 2 cos(x) + cos¹ (x) ²/ X syntax error. + C

A: Given query is to find the integral.

Q: your answer(s). Eliminate the parameter t. x = 4 sint - 4, y = 4 cost – 3

A:

Q: - sin sin -y = sin (x+y) Prove that cos Xcos 4 -y 4 -x sin 4 X - 4

A:

Q: cscx−sinx cos²x CSC X =

A: We need to prove that cscx-sinxcscx=cos2x

Q: cot(sec(x) -1 cot\sec

A: on  simplifying we get

Q: Cos (-x)= - Cosx

A: Let, cos-1(-x)=yThen,-x=cosyx=-cosy

Q: Prove sin(x+y)cos(x-y) = sinx/secx + cosy/cscy

A: I hope this can help you.

Q: Evaluate sec x dx VIn(sec x + tan x)

A: We will let,  ln( sec x+tan x) = t  to solve this question.

Q: sin[cos^-1(12/13)+tan^-1(4/3)]

A: Given:

Q: Evaluate sin" a cos a da.

A: Given : ∫sin4x cosx dx