sin x-2 cos 2 ド|N
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
Related questions
Question
![**Problem 10**
Solve for \( x \):
\[
\sin^{-1} x - 2 \cos^{-1} \left( \frac{\sqrt{2}}{2} \right) = -\frac{\pi}{2}
\]
**Explanation:**
This equation involves inverse trigonometric functions. You need to find the value of \( x \) that satisfies the equation. The inverse sine function \(\sin^{-1}\) and inverse cosine function \(\cos^{-1}\) are being used:
1. \(\sin^{-1} x\) refers to the angle whose sine is \( x \).
2. \(\cos^{-1} \left( \frac{\sqrt{2}}{2} \right)\) refers to the angle whose cosine is \(\frac{\sqrt{2}}{2}\).
The equation also involves simplifying expressions to solve for \( x \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F39618134-6ceb-48ac-ab5a-e0c16873beed%2F35080642-b461-45f9-87d5-9bd6b3d6bd01%2Fi6oma4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem 10**
Solve for \( x \):
\[
\sin^{-1} x - 2 \cos^{-1} \left( \frac{\sqrt{2}}{2} \right) = -\frac{\pi}{2}
\]
**Explanation:**
This equation involves inverse trigonometric functions. You need to find the value of \( x \) that satisfies the equation. The inverse sine function \(\sin^{-1}\) and inverse cosine function \(\cos^{-1}\) are being used:
1. \(\sin^{-1} x\) refers to the angle whose sine is \( x \).
2. \(\cos^{-1} \left( \frac{\sqrt{2}}{2} \right)\) refers to the angle whose cosine is \(\frac{\sqrt{2}}{2}\).
The equation also involves simplifying expressions to solve for \( x \).
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