sin t 1- cos t 6. s = 7. s = 12 - sec t + 1

Q: r=2(9+1)sin0

A: Since  Sin (0) = 0

Q: 1 + tan² dx

A:

Q: 4 A. sec* t- sec² t = tan´ t+tan* t

A: The given identity is,sec4t-sec2t=tan2t+tan4t

Q: sin 6xcos 3x dx

A:

Q: Sin X = 20 16 12

A:

Q: 2- cusx dx COSX Sinx +2 Sinx t5

A:

Q: sin(2w)dw =

A:

Q: sin3 COs x

A:

Q: Differentiate Sin (m sin-1 x)

A:

Q: sin 2x V2 – cos 2x dx

A:

Q: BIN 2 sin² x cos x dx

A:

Q: sin 2x (1 - 2 cos 2x)? dx 6.

A:

Q: Cos(10+x)

A: Here , We will apply the formula of Cos ( A+B) Cos(A+B) = [CosA CosB - SinA SinB ]

Q: 3 + cos 3x dx Evaluate sin 3x

A:

Q: Simplify cos(3Z45º) sin(5Z60°)

A:

Q: 25. sec (tan11 + csc¯l 1) →26. sec (cotl V3 + csc(-1)) ((2-) )- sec (-)) (The answer is not -a/6.)…

A: Trigonometry is the study of the relationship between the sides and angles of a right-angled…

Q: cos x sin x = csc 2x cos 3x sec 2x

A:

Q: Sin 3 o0Tt sin (5 sin 2nt) + Sin z00 Tit sin(ssinzr t)

A: Assume to simplify the given expression. sin300πtsin5sin2πt+sin300πtsin5sin2πt=2sin300πtsin5sin2πt

Q: COs o + Sin O = Sec0-tan Sec o CSoco

A:

Q: s cos 3ede CoS |- sinb

A: follow next step

Q: 2 sin 0- sin 0 = 0

A: The given equation 2sinθ-sinθ=0

Q: Sin °0 = Sec e-cos e Cos O = Sece-COs

A: Consider  sin2θcosθ=secθ-cosθ

Q: Find the Fourier series for the periodic function giving below -1, -π < t < -π/2 x(t) 0, -π/2 < t <…

A: Fourier series of the given periodic function

Q: sinx find: - dx 3 cos2x +1

A: find ∫sinxcos2x+13 dx first lets simplify it and then find the integral