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sin' a – cost 68. 4 - =D1 sin a – cos² a - cos? Cos 2

sin' a – cost 68. 4 - =D1 sin a – cos² a - cos? Cos 2

Trigonometry (11th Edition)
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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The second image is exercise 68 for the problem.
1 - COSE 57. cot - CSC r 1+cos x 1-sina 58. seca tan a 1+ sina cos 0+1 tan? 0 (sec0-tan 0)2+1 cose 59. sec0 1. 60. sec 0 csc0 tan 0 csc 6 =2 tan 0 61. = 2 sec2 0 1-sin0 1+sin0 62. = sec a +tana sec a tan a cota + 1 1+ tana 63. 1- tana cota -1 csc0 + cot 0 64. tan 0 + sin 0 coso cot 0 csc0 = 1 65. sin 0 cot0 66. sin? 0(1+ cot2 0) – 1= 0 4 CoS sin a 68. sin' a = 1 2 cos? a 2 =1-2 sin²t 70. 1+ cot? t 71. sin? a sec² a + sin? a csc a = s 72. tan? a sin² a = tan? a + cos? tan x sin x = cot 73. 1+ cos x sin0 1- cos x sine cose csco 74. 1- Cose 1+ cos0
Transcribed Image Text:1 - COSE 57. cot - CSC r 1+cos x 1-sina 58. seca tan a 1+ sina cos 0+1 tan? 0 (sec0-tan 0)2+1 cose 59. sec0 1. 60. sec 0 csc0 tan 0 csc 6 =2 tan 0 61. = 2 sec2 0 1-sin0 1+sin0 62. = sec a +tana sec a tan a cota + 1 1+ tana 63. 1- tana cota -1 csc0 + cot 0 64. tan 0 + sin 0 coso cot 0 csc0 = 1 65. sin 0 cot0 66. sin? 0(1+ cot2 0) – 1= 0 4 CoS sin a 68. sin' a = 1 2 cos? a 2 =1-2 sin²t 70. 1+ cot? t 71. sin? a sec² a + sin? a csc a = s 72. tan? a sin² a = tan? a + cos? tan x sin x = cot 73. 1+ cos x sin0 1- cos x sine cose csco 74. 1- Cose 1+ cos0
For Exercise 68, Section 5.2, Step 1: Factor the numerator on the left side: sin'a - costa = ( a - %3D a)( a + a) Step 2: After simplifying on the left hand side the resulting equation is one of the
Transcribed Image Text:For Exercise 68, Section 5.2, Step 1: Factor the numerator on the left side: sin'a - costa = ( a - %3D a)( a + a) Step 2: After simplifying on the left hand side the resulting equation is one of the
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