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sin 15° = √√A - √B

sin 15° = √√A - √B

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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if sin equals the formula below, then by using a half-angle formula, find A and B
The equation displayed on the image is: \[ \sin 15^\circ = \frac{1}{2} \left( \sqrt{A} - \sqrt{B} \right) \] This mathematical expression shows the sine of 15 degrees expressed in terms of two variables, \(A\) and \(B\), within a nested square root. The formula indicates a trigonometric identity or relation that involves simplifying the sine function using algebraic expressions.
Transcribed Image Text:The equation displayed on the image is: \[ \sin 15^\circ = \frac{1}{2} \left( \sqrt{A} - \sqrt{B} \right) \] This mathematical expression shows the sine of 15 degrees expressed in terms of two variables, \(A\) and \(B\), within a nested square root. The formula indicates a trigonometric identity or relation that involves simplifying the sine function using algebraic expressions.
Expert Solution
Step 1: Solution

Given: sin left parenthesis 15 degree right parenthesis equals 1 half square root of A minus square root of B end root

We have to find the values of A and B by using the half-angle formula.

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