Simplifying [ (n! / (n-1) !] gives: O (n+1) (n+2)! n!

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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### Simplifying [ (n! / (n-1)!) ] gives:

- ⃝ (n+1)
- ⃝ (n+2)!
- ⃝ n
- ⃝ n!

**Explanation:**

To simplify [ (n! / (n-1)!) ], we need to understand the factorial function. The factorial of a non-negative integer n, denoted by n!, is the product of all positive integers less than or equal to n. Mathematically, it is defined as:
\[ 
n! = n \times (n-1) \times (n-2) \times \ldots \times 1 
\]

Now, let's simplify the term \( \frac{n!}{(n-1)!} \):

Since \( n! = n \times (n-1) \times (n-2) \times \ldots \times 1 \) and \( (n-1)! = (n-1) \times (n-2) \times \ldots \times 1 \), we can rewrite \( n! \) as \( n \times (n-1)! \).

Thus,
\[ 
\frac{n!}{(n-1)!} = \frac{n \times (n-1)!}{(n-1)!} 
\]

The \( (n-1)! \) terms cancel out:
\[ 
\frac{n \times (n-1)!}{(n-1)!} = n 
\]

Therefore, the correct answer is:
\[ 
n 
\]

So, the correct option from the given multiple choices is:
- ⃝ n
Transcribed Image Text:### Simplifying [ (n! / (n-1)!) ] gives: - ⃝ (n+1) - ⃝ (n+2)! - ⃝ n - ⃝ n! **Explanation:** To simplify [ (n! / (n-1)!) ], we need to understand the factorial function. The factorial of a non-negative integer n, denoted by n!, is the product of all positive integers less than or equal to n. Mathematically, it is defined as: \[ n! = n \times (n-1) \times (n-2) \times \ldots \times 1 \] Now, let's simplify the term \( \frac{n!}{(n-1)!} \): Since \( n! = n \times (n-1) \times (n-2) \times \ldots \times 1 \) and \( (n-1)! = (n-1) \times (n-2) \times \ldots \times 1 \), we can rewrite \( n! \) as \( n \times (n-1)! \). Thus, \[ \frac{n!}{(n-1)!} = \frac{n \times (n-1)!}{(n-1)!} \] The \( (n-1)! \) terms cancel out: \[ \frac{n \times (n-1)!}{(n-1)!} = n \] Therefore, the correct answer is: \[ n \] So, the correct option from the given multiple choices is: - ⃝ n
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