Simplify those expressions to a sum of product form. Eliminate any redundant terms. Please step by step solution. 1,(X′Y ′)′(Z + X′)(X′ + Z′ + W ′) 2,(A+B′ +D′)(D+B+C)(D′ +C′ +A)(A+B+C)

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A: F = AB (B + C + D′)

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A: Given Boolean expression is x′z + x′y + xy′ + xy′z′  Input values are  x,y,z  Output is F.

Q: Simplify the following functional expression using Boolean algebra and its identities. List the…

A: F(x, y, z) = x(yz + y′z) + xy + x′y + xz = x(z(y + y')) + xy + x′y + xz               (Complement) =…

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