Simplify the equation then solve for the first derivative. 1 -1 11 = √√4c² – (0.4 – 0.2)² + ({(0.4) [₁ · +2sin-¹ (22)]} + (0.2) [x - - 2sin- 2. -¹ (2-²))) 2c 2c

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Simplify the equation then solve for the first derivative.
1
0.2
0.2
(0.4 – 0.2)² + ½({(0.4) |π
+ ½¹ ({(0.4) [x + 2sin¯¹ (2₂2)]} + (0.2) [R - 2sin-¹ (22)])
2
2c
2c
11 = √√4c²
4c²
Transcribed Image Text:Simplify the equation then solve for the first derivative. 1 0.2 0.2 (0.4 – 0.2)² + ½({(0.4) |π + ½¹ ({(0.4) [x + 2sin¯¹ (2₂2)]} + (0.2) [R - 2sin-¹ (22)]) 2 2c 2c 11 = √√4c² 4c²
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