Select a law then apply the law till trasforming what is given Jump to level 1Simplify mɅT to m1. Select a law from the right to apply--MATCheck1NextDistributive(аль) (алс) = ал(рус)(avb)^(avc) = av(bлc)CommutativeavbальComplementavaалтаIdentityалтavFLawsDouble negationיר===bvaблаTaaaFeedback? Jump to level 1Simplify (n^q)v-(-nvq) to n1. Select a law from the right to apply(n^q)v-(-nvq)Check1NextDistributive(аль) (алс)(avb)^(avc) ECommutativeavbальDe Morgan's7(аль)(avb)Conditionala-ba+bELawsa^(bvc)av(b^c)bvaБла¬av-b-ал-Бavb(a+b)^(b-a)Complementаva = Tалта = F¬TFIdentityалтEFETaירEaavF EaDouble negationaFe

The five connectives that are typically used in propositional logic are : OR (∨) AND (∧)…

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Simplify (n^q)v-(-nvq) to n 1. Select a law from the right to apply (n^q)v-(-nvq)

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Longest Common Subsequence

The Longest Common Subsequence (LCS) is defined as the longest subsequence that is shared by all of the given sequences, assuming that the subsequence's elements do not have to be in consecutive locations in the original sequences. It is used in the areas like bioinformatic, revision control systems like SVN and Git.

Question

100%

Select a law then apply the law till trasforming what is given

Jump to level 1
Simplify mɅT to m
1. Select a law from the right to apply
--MAT
Check
1
Next
Distributive
(аль) (алс) = ал(рус)
(avb)^(avc) = av(bлc)
Commutative
avb
аль
Complement
ava
алта
Identity
алт
avF
Laws
Double negation
יר
=
=
=
bva
бла
T
a
a
a
Feedback?

Jump to level 1
Simplify (n^q)v-(-nvq) to n
1. Select a law from the right to apply
(n^q)v-(-nvq)
Check
1
Next
Distributive
(аль) (алс)
(avb)^(avc) E
Commutative
avb
аль
De Morgan's
7(аль)
(avb)
Conditional
a-b
a+b
E
Laws
a^(bvc)
av(b^c)
bva
Бла
¬av-b
-ал-Б
avb
(a+b)^(b-a)
Complement
аva = T
алта = F
¬T
F
Identity
алт
EF
ET
aיר
Ea
avF Ea
Double negation
a
Fe

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