Simplify: m9 128a5 (c) V-24x5 (d) V65. (a) (b) All variables represent positive real numbers. We will factor each radicand into two factors, one of which is a perfect nth power. We can then apply the rule the nth root of a product is the product of the nth roots to simplify the radical expression. (a) The greatest perfect-square factor of m° is m8. m9 = m8. m Write m° in factored form as m8 - m. = V m8 Vm Use the product rule for radicals. 8 Vm Simplify V m8. (b) Since the greatest perfect-square factor of 128 is 64 and the greatest perfect-square factor of a5 is a“, the largest perfect-square factor of 128a5 is 64 We write 128a as 64a* - 2a and proceed as follows: 128a5 = V 64a · 2a Write 128a5 in factored form as 64a - 2a. = V 64a4 . V 2a Use the product rule for radicals. = 8a? /2a Simplify V64a4. (c) We write -24x as -8x - 3x² and proceed as follows: V-24x5 = V-8x³ - 3x² 8x is the largest perfect-cube factor of 24x. Since the radicand is negative, we factor it using -8x. = V-8x3 · V3x² Use the product rule for radicals. 8 V3x Simplify V-8x³.

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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EXAMPLE 2 Simplify:
(a)
V mº
(b)
128a5 (c)
-24x5
(d) Vab5.
All variables represent positive real numbers.
Strategy
We will factor each radicand into two factors, one of which is a perfect nth power.
Why
We can then apply the rule the nth root of a product is the product of the nth roots to simplify the radical expression.
Solution
(a) The greatest perfect-square factor of mº is m³.
m8 . m
Write m9 in factored form as m8 · m.
m8
m
Use the product rule for radicals.
8.
Vm Simplify v m³.
(b) Since the greatest perfect-square factor of 128 is 64 and the greatest perfect-square factor of a is a“, the largest perfect-square factor of 128a5 is 64
We write 128a as 64a“ · 2a and proceed as follows:
128a5
64a4 · 2a
Write 128a in factored form as 64a4 · 2a.
64a4
Use the product rule for radicals.
V 2a
= 8a?
2a
Simplify v 64a4.
%D
(c) We write -24x5 as -8x³· 3x2 and proceed as follows:
3
-24x5
V-8x3 · 3x2
8x³ is the largest perfect-cube factor of 24x. Since the radicand is negative, we factor it using -8x3.
%3D
3
-8x3 · V 3x2
Use the product rule for radicals.
%3D
8
V3x2 Simplify V-8x3.
Transcribed Image Text:EXAMPLE 2 Simplify: (a) V mº (b) 128a5 (c) -24x5 (d) Vab5. All variables represent positive real numbers. Strategy We will factor each radicand into two factors, one of which is a perfect nth power. Why We can then apply the rule the nth root of a product is the product of the nth roots to simplify the radical expression. Solution (a) The greatest perfect-square factor of mº is m³. m8 . m Write m9 in factored form as m8 · m. m8 m Use the product rule for radicals. 8. Vm Simplify v m³. (b) Since the greatest perfect-square factor of 128 is 64 and the greatest perfect-square factor of a is a“, the largest perfect-square factor of 128a5 is 64 We write 128a as 64a“ · 2a and proceed as follows: 128a5 64a4 · 2a Write 128a in factored form as 64a4 · 2a. 64a4 Use the product rule for radicals. V 2a = 8a? 2a Simplify v 64a4. %D (c) We write -24x5 as -8x³· 3x2 and proceed as follows: 3 -24x5 V-8x3 · 3x2 8x³ is the largest perfect-cube factor of 24x. Since the radicand is negative, we factor it using -8x3. %3D 3 -8x3 · V 3x2 Use the product rule for radicals. %3D 8 V3x2 Simplify V-8x3.
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