SIMPLE BATCH DISTILLATION Mole fraction of methanol in the feed = X0 = XF = 0.31 Mole fraction of methanol in the residue = Xn = XR = 0.06 F = Total number of moles in the feed = 40.12 I want full answer with all solution steps ASAP PLZ
SIMPLE BATCH DISTILLATION Mole fraction of methanol in the feed = X0 = XF = 0.31 Mole fraction of methanol in the residue = Xn = XR = 0.06 F = Total number of moles in the feed = 40.12 I want full answer with all solution steps ASAP PLZ
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Question
SIMPLE BATCH DISTILLATION
Mole fraction of methanol in the feed = X0 = XF = 0.31
Mole fraction of methanol in the residue = Xn = XR = 0.06
F = Total number of moles in the feed = 40.12
I want full answer with all solution steps ASAP PLZ
Transcribed Image Text:1
Y*
Y* - X
Y= (;
No
y*-X
XF = Xo =
Yo =
0.053
0.275
0.074
0.356
0.087
0.395
0.108
0.44
0.129
0.488
0.164
0.537
0.191
0.572
0.268
0.648
0.294
0.666
0.352
0.704
0.939
Yn =
XR = Xp =
Transcribed Image Text:NOTE:
Plot (x) versus calculated (y), the integral is obtained by finding the area under the curve :
F
In
R
A curve
F = Total number of moles in the feed =
we can calculate R =
In = Out
D = F-R=.
F = Total no. of moles in the feed, R = Total no. of moles in the residue,
D = Total no. of moles in the distillate
F =R+ D,
Where:
MATERIAL BALANCE ON THE METHANOL
MF = MR + Mp
Mo = MF- MR =,
Where : Mo = Moles of ethanol in the distillate
MATERIAL BALANCE ON THE WATER
W; = WR + Wo
Wo = WF - WR =
Where:
Wo = Moles of water in the distillate
%3D
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