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SIGNAL a) – 1,500 Ο 10 ΚΩ Ο 5 ΚΩ wwwww 2 ΚΩ 2 ΚΩ R = 1 kΩ +15 V β = 100 10 ΚΩ 5 ΚΩ www 2 ΚΩ -- 2 ΚΩ Ri = 1 KΩ β = 100 OUTPUT

SIGNAL a) – 1,500 Ο 10 ΚΩ Ο 5 ΚΩ wwwww 2 ΚΩ 2 ΚΩ R = 1 kΩ +15 V β = 100 10 ΚΩ 5 ΚΩ www 2 ΚΩ -- 2 ΚΩ Ri = 1 KΩ β = 100 OUTPUT

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question

In the circuit given in the figure, the AC input resistance values ​​of each floor are 1 Kohm.  Accordingly, find the value of the voltage gain of each floor.

SIGNAL a) — 1,500 b) Ο 66, 200 c) Ο 500,1 d) — 80, 500 0 10 ΚΩ δια wwwww 5 ΚΩ . 2 ΚΩ 2 ΚΩ R = 1 kΩ +15 V β = 100 10 ΚΩ 5 ΚΩ wwww 2 ΚΩ --- 2 ΚΩ Ri = 1 KΩ β = 100 OUTPUT
Transcribed Image Text:SIGNAL a) — 1,500 b) Ο 66, 200 c) Ο 500,1 d) — 80, 500 0 10 ΚΩ δια wwwww 5 ΚΩ . 2 ΚΩ 2 ΚΩ R = 1 kΩ +15 V β = 100 10 ΚΩ 5 ΚΩ wwww 2 ΚΩ --- 2 ΚΩ Ri = 1 KΩ β = 100 OUTPUT
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