Sigh in 0.65 0.60 0.55 0.50 Run #20 0.45 0.40 0.35 0.30 0.0 0.2 0.4 0.6 0.8 1.0 1.2 1.4 1.6 1.8 2.0 2.2 2.4 2.6 2.8 Time (s) 3.0 3.2 0.4 0.3 Linear 0.2 mt + b m =-0.18855 ± 0.00137 b -0.31353 ± 0.00246 Run #20 0.1 0.0 r -0.998 -0.1 -0.2 -0.3 0.0 0.2 0.4 0.6 0.8 1.0 1.2 1.4 1.6 2.0 2.2 2.4 2.6 2.8 3.0 3.2 Time (s) (Graph title here] A Position (m) A Velocity (m/s)
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
Fill in the blanks below based of the information in the graph
A.) Initally the cart is moving to the blank ( left or right)
B.) and the cart is blank( speeding up, moving at a constant velocity or slowing down)
C.) the acceleration of the cart has how many significant numbers?
D.) the final result for the acceleration is blank +/- blank
E.) from the final results of your line fot equation, determine that the car turned around at blank seconds
![Arrange
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0.65
0.60
0.55
0.50
Run #20
0.45
0.40
0.35
0.30
0.0
0.2
0.4
0.6
0.8
1.0
12
1.4
1.6
1.8
2.0
2.2
2.4
2.6
2.8
Time (s)
3.0
3.2
0.4
0.3
Linear
mR क bi
m =-0.18855±0.00137
0.2
Run #20
0.1
b -0.31353 ±0.00246
0.0
r=.0.998
-0.1
-0.2
-0.3
0.0
0.2
0.4
0.6
0.8
10
1.2
1.4
Time (s)
16
2.0
2.2
2.4
2.6
2.8
3.0
3.2
[Graph title here]
OFocus,
A Velocity (m/s)
A Position (mn)
II](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe2d19cbc-ad9d-489a-8c14-e512e89b3939%2Fb04e8946-da86-4e6f-a9b3-8a96d8a41990%2Fya5ie28_processed.jpeg&w=3840&q=75)
At time 1.6 second graph changes as the velocity is now increasing in negative direction so the acceleration changes at the same time which is most significant
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