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shown, with the resulting major product being an internal alkyne? 1) NaNH2 2) R-Br Br Br Br Br Br II III IV V O Il and IV O I, II, IV II, IV, V O l and III O II, III, V

shown, with the resulting major product being an internal alkyne? 1) NaNH2 2) R-Br Br Br Br Br Br II III IV V O Il and IV O I, II, IV II, IV, V O l and III O II, III, V

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Organic Chemistry Question #### Problem: Which of the alkyl bromides listed would work as a reagent in step 2 of the reaction sequence shown, with the resulting major product being an internal alkyne? #### Reaction Sequence Diagram: The diagram presents a two-step reaction sequence: 1) The alkyne is treated with sodium amide (NaNH₂). 2) The resulting product is reacted with an alkyl bromide (R-Br). #### Chemical Structures: Five chemical structures labeled I to V are provided, each representing an alkyl bromide. 1. **Structure I**: Cyclopentyl bromide 2. **Structure II**: (3-Bromopropyl) methylethyl 3. **Structure III**: 2-Bromobutane 4. **Structure IV**: 1-Bromobutane 5. **Structure V**: Cyclohexyl bromide #### Answer Options: - ○ II and IV - ○ I, II, IV - ○ III, IV, V - ○ I and III - ○ II, III, V #### Explanation: To form an internal alkyne, the resulting product after reaction with the alkyl bromide should contain a carbon-carbon triple bond within the carbon chain, not at the terminal position. #### Analysis of Options: - **II and IV**: - **II**: 3-Bromopropyl methylethyl - **IV**: 1-Bromobutane - **I, II, IV**: - **I**: Cyclopentyl bromide - **II**: 3-Bromopropyl methylethyl - **IV**: 1-Bromobutane - **III, IV, V**: - **III**: 2-Bromobutane - **IV**: 1-Bromobutane - **V**: Cyclohexyl bromide - **I and III**: - **I**: Cyclopentyl bromide - **III**: 2-Bromobutane - **II, III, V**: - **II**: 3-Bromopropyl methylethyl - **III**: 2-Bromobutane - **V**: Cyclohex
Transcribed Image Text:### Organic Chemistry Question #### Problem: Which of the alkyl bromides listed would work as a reagent in step 2 of the reaction sequence shown, with the resulting major product being an internal alkyne? #### Reaction Sequence Diagram: The diagram presents a two-step reaction sequence: 1) The alkyne is treated with sodium amide (NaNH₂). 2) The resulting product is reacted with an alkyl bromide (R-Br). #### Chemical Structures: Five chemical structures labeled I to V are provided, each representing an alkyl bromide. 1. **Structure I**: Cyclopentyl bromide 2. **Structure II**: (3-Bromopropyl) methylethyl 3. **Structure III**: 2-Bromobutane 4. **Structure IV**: 1-Bromobutane 5. **Structure V**: Cyclohexyl bromide #### Answer Options: - ○ II and IV - ○ I, II, IV - ○ III, IV, V - ○ I and III - ○ II, III, V #### Explanation: To form an internal alkyne, the resulting product after reaction with the alkyl bromide should contain a carbon-carbon triple bond within the carbon chain, not at the terminal position. #### Analysis of Options: - **II and IV**: - **II**: 3-Bromopropyl methylethyl - **IV**: 1-Bromobutane - **I, II, IV**: - **I**: Cyclopentyl bromide - **II**: 3-Bromopropyl methylethyl - **IV**: 1-Bromobutane - **III, IV, V**: - **III**: 2-Bromobutane - **IV**: 1-Bromobutane - **V**: Cyclohexyl bromide - **I and III**: - **I**: Cyclopentyl bromide - **III**: 2-Bromobutane - **II, III, V**: - **II**: 3-Bromopropyl methylethyl - **III**: 2-Bromobutane - **V**: Cyclohex
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