Shown below is a small particle of mass 39 g that is moving at a speed of 10 m/s when it collides with and sticks to the edge of a uniform solid cylinder. The cylinder is free to rotate about the axis through its center and perpendicular to the page. The cylinder has a mass of 0.8 kg and a radius of 18 cm and is initially at rest.
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Shown below is a small particle of mass 39 g that is moving at a speed of 10 m/s when it collides with and sticks to the edge of a uniform solid cylinder. The cylinder is free to rotate about the axis through its center and perpendicular to the page. The cylinder has a mass of 0.8 kg and a radius of 18 cm and is initially at rest.
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- A 0.02 kg mass red object (bead) is moving at a speed of 10.0 m/s when it sticks to the edge of a uniform solid cylinder. The cylinder is free to rotate about its axis through its center and has a mass of 0.5 kg , a radius of 0.25 m and is initially at rest. I = 1/2MR2^2 a) What is the angular velocity of the system after the collision? b) How much kinetic energy is lost in the collision? c) If the angular position of the Cylinder varies as θ(t)=3.2t-t^2 find the centripetal acceleration of the red object (bead). d) A cord is now wrapped around the cylinder. Use the work energy theorem to find the angular velocity of the cylinder after 5.0m of cord have been removed by a 40N Force. e) If the 40N force on the cord is replaced by a 40-N weight, what is the angular velocity of the cylinder after 5.0m of cord has unwound?As shown in Figure , a 0.500 kg stone moving horizontally with a speed of 2.25 m/s collides with a 0.750 m long stationary vertical uniform rod. The rod has a mass of 1.50 kg and is fixed to the ground by a frictionless hinge. After the collision, the stone drops vertically down to the ground. What is the angular speed of the rod just after the collision? 0.25 m A) 2.00 rad/s B) 1.00 rad/s C) 3.00 rad/s D) 4.00 rad/s E) 5.00 rad/s stone v = 2.25 m/s 0.75 m HingeA potter's disk spins from rest up to 3.8 rev/s in 15 s. The disk has a mass 3.5 kg and radius 24.0 cm. What is the angular momentum (in kg · m2/s) of the disk at t = 5 s? (Enter the magnitude.) What is the angular momentum (in kg · m2/s) of the disk at t = 10 s?(Enter the magnitude.)
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- A 2 kg mass is located at r = 2m +3m and has. velocity v = 4 m/s - 1m/s What is the angular momentum of the massA lawnmower blade has a length of 0.75 m and a mass of 1.5 kg. The blade rotates around its center at an angular velocity of 500 re. The end of the blade hits a 0.25 kg croquet ball (point mass), and the ball sticks to the blade. min Before the collision, the ball was stationary. After the collision, the ball will be moving at the same angular velocity as the blade at a distance of half of the blade length from the axis of rotation. Treat the blade as a rod rotating around its center. The final angular velocity of the lawnmower blade and croquet ball combo is rad SA 200-kg, 2.0-m-radius, merry-go-round in the shape of a flat, uniform, circular disk parallel to level ground is rotating at 1.2 cycles/second about an axis through its center of mass and perpendicular to the ground. A 50-kg boy jumps onto the edge of the merry-go round and lands at a fixed point. What is the angular velocity of the merry-go-round after the boy lands on it? Hint: = (1/2)mR2 where m is the mass of the disk and R is the radius of the disk.