Shown below is a 45 kg crate that is pushed at constant velocity a distance 8.1 m up a 30° incline by the horizontal force F. The coefficient of kinetic friction between the crate and the incline is u 0.49. (Due to the nature of this problem, do not use rounded intermediate values in your calculations-including answers submitted in WebAssign.) 45 kg 30° (a) Calculate the work done (in J) by the applied force. 3816.572388 J (b) Calculate the work done (in J) by the frictional force -1517.37614 X J (c) Calculate the work done (in J) by the gravitational force. -1787.8725 (d) Calculate the work done (in J) by the net force. 5048.850699 J LL

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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Please show me how to work this. Please don't round any figures.

Shown below is a 45 kg crate that is pushed at constant velocity a distance 8.1 m up a 30° incline by the horizontal force F. The coefficient of kinetic friction between the crate and the incline is u
0.49. (Due to the nature of this
problem, do not use rounded intermediate values in your calculations-including answers submitted in WebAssign.)
45 kg
30°
(a) Calculate the work done (in J) by the applied force.
3816.572388 J
(b) Calculate the work done (in J) by the frictional force
-1517.37614 X J
(c) Calculate the work done (in J) by the gravitational force.
-1787.8725
(d) Calculate the work done (in J) by the net force.
5048.850699 J
LL
Transcribed Image Text:Shown below is a 45 kg crate that is pushed at constant velocity a distance 8.1 m up a 30° incline by the horizontal force F. The coefficient of kinetic friction between the crate and the incline is u 0.49. (Due to the nature of this problem, do not use rounded intermediate values in your calculations-including answers submitted in WebAssign.) 45 kg 30° (a) Calculate the work done (in J) by the applied force. 3816.572388 J (b) Calculate the work done (in J) by the frictional force -1517.37614 X J (c) Calculate the work done (in J) by the gravitational force. -1787.8725 (d) Calculate the work done (in J) by the net force. 5048.850699 J LL
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