Shown below are birth weights (in kilograms) of male babies born to mothers taking a special vitamin supplement. Assume that we want to use the sample data to test the claim that the sample is from a population with a standard deviation equal to 0.502 kg, which is the standard deviation for the population not given the special vitamin supplement. Use the data and the claim given to identify the null and alternative hypotheses and the test statistic. What is the sampling distribution of the test statistic? 3.783.283.954.064.293.793.273.113.293.133.563.793.123.164.074.09
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Shown below are birth weights (in kilograms) of male babies born to mothers taking a special vitamin supplement. Assume that we want to use the sample data to test the claim that the sample is from a population with a standard deviation equal to 0.502 kg, which is the standard deviation for the population not given the special vitamin supplement.
Use the data and the claim given to identify the null and alternative hypotheses and the test statistic. What is the sampling distribution of the test statistic?
3.78
3.28
3.95
4.06
4.29
3.79
3.27
3.11
3.29
3.13
3.56
3.79
3.12
3.16
4.07
4.09
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- Use the data and table below to test the indicated claim about the means of two populations. Assume that the two samples are independent simple randor samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Make sure you identify all values. An Exercise Science instructor at IVC was interested in comparing the resting pulse rates of students who exercise regularly and the pulse rates of those who de not exercise regularly. Independent simple random samples of 16 students who do not exercise regularly and 12 students who exercise regularly were selected and the resting pulse rates (in beats per minute) were recorded. The summary statistics are presented in the table below. Is there compelling statistical evidence that the mean resting pulse rate of people who do not exercise regularly is greater than the mean resting pulse rate of people who exercise regularly? Use a significance value of 0.05. Two-Sample T-Test Sample…Data on the weights (lb) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. a. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. What are the null and alternative hypotheses? OA. Ho: H₁ H₂ H₁: Hy #4₂ OC, Hoi ky tuy H₁: Hy O L P H command n X S Time Remaining: 01:13:11 V : • Diet H₁ 30 0.79861 lb 0.00445 lb ; x { [ option ? I Regular H₂ 30 0.80936 lb 0.00742 lb Next deleteA 0.1 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is less than 0.5. Assume that sample data consists of 78 girls in 169 births, so the sample statistic of 613 results in a z score that is 1 standard deviation below 0. Complete parts (a) through (h) below.Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING...Question content area bottomPart 1a. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below.A.H0: p≠0.5H1: p<0.5B.H0: p=0.5H1: p≠0.5C.H0: p=0.5H1: p<0.5D.H0: p=0.5H1: p>0.5Part 2b. What is the value of α?α=enter your response here (Type an integer or a decimal.)Part 3c. What is the sampling distribution of the sample statistic? Normal distribution Student (t) distribution χ2Part 4d. Is the test two-tailed, left-tailed, or right-tailed? Right-tailed…
- A 0.01 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is different from 0.5. Assume that sample data consists of 55 girls in 100 births, so the sample statistic of 1120 results in a z score that is 1 standard deviation above 0. Complete parts (a) through (h) below.Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING...Question content area bottomPart 1a. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below.A.H0: p=0.5H1: p≠0.5B.H0: p=0.5H1: p>0.5C.H0: p=0.5H1: p<0.5D.H0: p≠0.5H1: p=0.5Part 2b. What is the value of α?α=enter your response here (Type an integer or a decimal.)Part 3c. What is the sampling distribution of the sample statistic? χ2 Normal distribution Student (t) distributionA study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.10 significance level for both parts. a. Test the claim that the two samples are from populations with the same mean. What are the null and alternative hypotheses? OA. Ho: H₁ H₂ H₁: Hq ZH₂ OC. Ho: H₁ H₂ H₁: Hy > H₂ The test statistic, t, is. (Round to two decimal places as needed.) (Round to three decimal places as needed.) The P-value is State the conclusion for the test. C... OB. Ho: H₁ H₂ H₁: Hy #H₂ OD. Ho: Hg #U2 H₁: HyConsider the sample data 2, 4, and 6 with population standard deviation of 1.633. Compute the following using the formulas in Central Limit Theorem. N=3 n=2 sample mean sample standard deviation Choose... sample variance Choose... + Please answer all parts of the question.You may need to use the appropriate appendix table or technology to answer this question. Consider the following data for two independent random samples taken from two normal populations. Sample 1 10 7 13 798 Sample 2 978 459 (a) Compute the two sample means. Sample 1 Sample 2 (b) Compute the two sample standard deviations. (Round your answers to two decimal places.) Sample 1 Sample 2 (c) What is the point estimate of the difference between the two population means? (Use Sample 1-Sample 2.) (d) What is the 90% confidence interval estimate of the difference between the two population means? (Use Sample 1-Sample 2. Round your answers to two decimal places.) -0.29 x to 4.29 X TutorialA study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. a. Test the claim that the two samples are from populations with the same mean. What are the null and alternative hypotheses? OA. Ho: H₁ H₂ H₁: H₁ H₂ OC. Ho: H₁ H¹/₂ H₁: H₁Pathological gambling is an impulse-control disorder. The National Gambling Impact Study Commission randomly selected 2877 adults and found that 193 were pathological gamblers. Is there evidence to conclude that more than 6% of the adult population are pathological gamblers as claimed by the American Psychiatric Association? Use α = 0.1 to test the claimListed in the data table are IQ scores for a random sample of subjects with medium lead levels in their blood. Also listed are statistics from a study done of IQ scores for a random sample of subjects with high lead levels. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. a. Use a 0.01 significance level to test the claim that the mean IQ scores for subjects with medium lead levels is higher than the mean for subjects with high lead levels. What are the null and alternative hypotheses? Assume that population 1 consists of subjects with medium lead levels and population 2 consists of subjects with high lead levels. OA. Ho: H₁1 H₂ H₁ H₁ H₂ OC. Ho: H₁ H₂ H₁: H₁ H₂ The test statistic is 0.20. (Round to two decimal places as needed.) The P-value is 0.423. (Round to three decimal places as needed.) State the conclusion for the…Find Test Statistic, P value, and Z score.Given in the table are the BMI statistics for random samples of men and women. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. a. Use a 0.05 significance level, and test the claim that males and females have the same mean body mass index (BMI). What are the null and alternative hypotheses? OA. Ho: H₁ H₂ H₁ H₁ H₂ OC. Ho: H₁ H₂ H₁: H₁ H₂ The test statistic, t, is The P-value is . (Round to two decimal places as needed.) (Round to three decimal places as needed.) State the conclusion for the test. OB. Ho: H₁ H₂ H₁: H₁ H₂ OD. Ho: H₁ = H₂ H₁: H1 H₂ O A. Fail to reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that men and women have the same mean BMI. O B. Fail to reject the null hypothesis. 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