Show your table.10. TRANSIT RULE. Given in the accompanying tabulations are observed and calculated data fortwo different traverses.LATITUDEDEPARTUREAZIMUTHLINEDISTANCEFROM SOUTH+N-s+E-w352.0499°45'154 00242 30353 15'60.49164.64AB:357.20 m80.30вс183.18CD430.05198.57381.46422.2349.97DA425.18+ 423.70-422.23+ 431.43<-432.34Sums1395.61 m(ESL)(ΣΕD)(Z WD)(ENL)(D)COURSEAZIMUTHLATITUDEDEPARTURELENGTHFROM NORTH+N-S+E-W380. 38 m51 9.30CDo*50'296*06'205 54'135 20'380. 345.53DE228.46466.35303.08EF693.87624.18FG417.98297.27293.8333 27'95 39'GH403.93337.03222.65HC249.0024.51247.79Sums2664.46 m+945.83-945.96+769.80-769.43(D)ENL)(ESL)CZED)(EWD)For each set of traverse data, balance the latitudes and departures by the transit rule. Alsodetermine the linear error of closure, bearing of the side of error, and the precision of themeasurements made. Tabulate all observed and calculated values into a convenient format andprepare a sketch of the adjusted traverse.

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Show your table. 10. TRANSIT RULE. Given in the accompanying tabulations are observed and calculated data for two different traverses. LATITUDE DEPARTURE AZIMUTH LINE DISTANCE FROM SOUTH -s +N +E -W 352.04 80.30 99°45' 154*00! 242 30 353 15' 60.49 AB. вс 357.20 m 164.64 198.57 183. 18 381.46 430.05 425.18 CD 422.23 49.97 DA + 423. 70 +431.43 -432.34 -422.23 Sums 1395. 61m (ENL) (ESL) (ZED) (ZWD) (D) AZIMUTH LATITUDE DEPARTURE COURSE LENGTH FROM NORTH +N -s +E -W 380. 38 m 51 9.30 CD O*50' 296*06' 205 54' 135 20' 33 27' 95 39' 380. 34 5.53 DE 228.46 466.35 303.08 EF 693.87 624.18 FG 417.98 297.27 293.83 GH 403.93 337.03 222.65 HC 249.00 24.51 247.79 Sums 2664.46 m +945.83 -945.96 +769.80 -769.43 (D) ENL) (ESL) CEED) (ΣWD) For each set of traverse data, balance the latitudes and departures by the transit rule. Also determine the linear error of closure, bearing of the side of error, and the precision of the measurements made. Tabulate all observed and calculated values into a convenient format and prepare a sketch of the adjusted traverse.

Show your table. 10. TRANSIT RULE. Given in the accompanying tabulations are observed and calculated data for two different traverses. LATITUDE DEPARTURE AZIMUTH LINE DISTANCE FROM SOUTH -s +N +E -W 352.04 80.30 99°45' 15400! 242 30 353 15' 60.49 AB. вс 357.20 m 164.64 198.57 183. 18 381.46 430.05 425.18 CD 422.23 49.97 DA + 423. 70 +431.43 -432.34 -422.23 Sums 1395. 61m (ENL) (ESL) (ZED) (ZWD) (D) AZIMUTH LATITUDE DEPARTURE COURSE LENGTH FROM NORTH +N -s +E -W 380. 38 m 51 9.30 CD O50' 296*06' 205 54' 135 20' 33 27' 95 39' 380. 34 5.53 DE 228.46 466.35 303.08 EF 693.87 624.18 FG 417.98 297.27 293.83 GH 403.93 337.03 222.65 HC 249.00 24.51 247.79 Sums 2664.46 m +945.83 -945.96 +769.80 -769.43 (D) ENL) (ESL) CEED) (ΣWD) For each set of traverse data, balance the latitudes and departures by the transit rule. Also determine the linear error of closure, bearing of the side of error, and the precision of the measurements made. Tabulate all observed and calculated values into a convenient format and prepare a sketch of the adjusted traverse.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Traverse Survey

Traverse surveying is a popular method of surveying. Traversing is that type of survey where several connected survey lines form a framework and the directions and lengths of the survey lines are measured with the help of a tool to measure angles and tape or chain respectively. Traverse networks involve placing survey stations in a queue or trail and using pre-tested points as a basis for looking at the next point. This type of surveying is different from Tacheometric surveying, where only angles are measured and the process of chaining is reduced.

Question

Show your table.
10. TRANSIT RULE. Given in the accompanying tabulations are observed and calculated data for
two different traverses.
LATITUDE
DEPARTURE
AZIMUTH
LINE
DISTANCE
FROM SOUTH
+N
-s
+E
-w
352.04
99°45'
154 00
242 30
353 15'
60.49
164.64
AB:
357.20 m
80.30
вс
183.18
CD
430.05
198.57
381.46
422.23
49.97
DA
425.18
+ 423.70
-422.23
+ 431.43
<-432.34
Sums
1395.61 m
(ESL)
(ΣΕD)
(Z WD)
(ENL)
(D)
COURSE
AZIMUTH
LATITUDE
DEPARTURE
LENGTH
FROM NORTH
+N
-S
+E
-W
380. 38 m
51 9.30
CD
o*50'
296*06'
205 54'
135 20'
380. 34
5.53
DE
228.46
466.35
303.08
EF
693.87
624.18
FG
417.98
297.27
293.83
33 27'
95 39'
GH
403.93
337.03
222.65
HC
249.00
24.51
247.79
Sums
2664.46 m
+945.83
-945.96
+769.80
-769.43
(D)
ENL)
(ESL)
CZED)
(EWD)
For each set of traverse data, balance the latitudes and departures by the transit rule. Also
determine the linear error of closure, bearing of the side of error, and the precision of the
measurements made. Tabulate all observed and calculated values into a convenient format and
prepare a sketch of the adjusted traverse.

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Please hep me sir
TRANSIT RULE. pls make use of table and draw the traverse
8. Compute for the following and show the tabulated solutions: Azimuth LINES Length (S) АВ 1020.87 168d35m ВС 1117.26 263d30m CD 660.08 304d25m DE 495.85 5d30m EF 850.62 46d15m FA 855.45 112d30m (lengths in 3 dec. places; bearings in deg-mm-ss) a. Using Transit Rule, solve for adjusted latitudes, departures, distances, and bearings for all the traverse lines Lines Adj. Latitude Adj. Departure Adj. Length Adj. Bearing AB BC CD DE EF FA
Q3): The following data were collected while running a closed traverse ABCDA. Calculate: Line AB BC CD DA 2- Linear misclosure 3- Traverse precision Length(m) 330 866.8846 411.0045 827 Sum=2435.15 Azimuth 181°25' 89°50' 355°00' 264°18'20" Point A B C 1358.7 D 1323.167 A (calculated) 500 Easting 500 491.84 = = Northing 500 170.1 172.62 582.059 500
PROBLEM 1. Given in the accompanying tabulation are the adjusted latitude and adjusted departure of a closed traverse. Calculate the area by the DMD method LINE ADJ ADJ LAT DEP AB - 125.055 + 196.387 BC +20.241 + 241.003 CD +180.107 + 65.326 DE +210.169 - 104.519 EF -74.003 - 260.516 FA - 211.459 - 137.681
3. The following data if a closed traverse is shown in the technical description. The area of the closed traverse is 63147.05 sq. m. LINES AB BC CD LAT. a -240.20 -160.00 DA 179.70 Solve for the unknown variables. DEP. 120 с e -220 DMD b d f 8 2A 26460.0 X -86480.0 39534.0
Situation 4] From the given data ofa dosed traverse, The adjusted bearing of BC using compassrule. The adjusted bearing of DA using compass rule. The total area using Coordinates method. The total area using Double Parallel Distance method. i. ii. i. iv. Distance, m 368.76 Bearing N15°18'E S85046'E S18°30W N77035W Line АВ ВС 645.38 CD 467.86 DA 593.00
4.) (10 Points) Latitude and Departure Given the observed data of a closed traverse, determine the latitudes and departures of each line. Line Length 161.460 m Azimuth from North AB 228°20' ВС 180.490 m 267°43 CD 171.830 m 352°01' DE 229.700 m 82°12' EA 130.550 m 131°48' * Indicate the sign for latitude and departure Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.
The question is related to survey subject , kindly do it fast and stepwisley thanks....
HI! HELP ME WITH THIS PLEASE. TYSM
6. LATITUDES tabulations are the observed data pertaining to four diffe- rent traverses. CoOmpute and tabulate the latitudes and departures of each course. AND DEPARTURERS. Given in the accompanying AZIMUTH FROM SOUTH LINE LENGTH BEARING LINE DISTANCE NO0° 42'E S85 57'E so3* 04'w S52 51'w 242 30' 353 15' 99 45' 154 00 AB 732.72m JK 430.05 m BC 324.78 KL 425.18 CD 477.24 LM 357.20 DA 388.08 MJ 183.18 AZIMUTH COURSE LENGTH COURSE LENGTH BEARING FROM NORTH 228 20' 267 43' 352 01' 82 12' 131 48' N59 33'E S39 18'E so6*35'w NI7:48'w N70°59'w 1-2 161.46 m 1-2 427.00 m 301.95 180.49 2-3 3-4 2-3 171.83 3-4 445.66 4-5 229.70 326.73 434.50 4-5 5-1 130.55 5-1 7. ERROR OF CLOSURE. Given the following tabulated data for vevs
Following are the data gathered from the traverse: Lat Dep DPD 2A 399.790 0 565.388565.277 -350.184605.780 -564.112-205.360 -50.882-965.697 Express all answer unitless and with 3 decimals for A to J No new data to sav