Show your calculation for the preparation of 100 mL of a solution of approximately 4 mM (that is 4 x 10-3 M) o-nitrophenol (M.W. 139.11 g mol-1) using 0.40 M Na2CO3 as the solvent.

Name: Date: Section: Prelaboratory Assignment: Determination of Molecular Weight Through Freezing Point Depression Analysis 1. What is the vapor pressure at 20'C of a solution of 3.50 g of naphthalene C1Hg in 25.0 g of benzene (v.p. pure benzene =74.7 mm Hg at 20°C) 2. Calculate the freezing point of a solution of 25 mL of CH,OH (d = 0.792 g/ml) in 325 mL of water (d= 1.00 g/ml, k, 1.86 °C/m). %3D %3D %3D A5.00

For each solute, tap the button under the better solvent. solute Which is the better solvent? CH3(CH,),CH3 H,O H,O :0: :0: NH, - NH2 CH3- CH3 S - CH;CH,OH :0: :0: :0: || C CH,— CH, —с — он - НО CH, — S — сH, -

(Correct!) The mass percent composition of an organic compound showed that it contained 40.0% C, 6.7% H and 53.3% O. A solution of 0.673 g of the solid in 28.1 g of the solvent diphenyl gave a freezing point depression of 1.6 Celsius. Calculate the molecular formula of the solid. (Kf for diphenyl is 8.00°C/m.) C4H8O4 (Your correct answer) CH₂0 C3H405 C3H603 C₂H4O2

What is the freezing point (°C) of a solution prepared by dissolving 13.5 g of (NH4)2SO4 (formula weight = 132 g/mol) in 100 g of water? The molal freezing point depression constant for water is 1.86°C/m. Assume complete dissociation in solution. Express your answer in decimal notation and to 2 decimal places, without units.

12 g of compound “Y” dissolves in 10 ml of acetone at 25 oC and 0.85 g of the same compound dissolves in 10 ml of boiling acetone. What volume of acetone would be required to purify a 5.0 g sample of compound?

10. A solution was prepared by dissolving 5.76 g of KCI MgCl2.6H20 (277.85 g/mol) in sufficient water to give 2.000 L. Calculate (d) the weight/volume percentage of KCI. MgCl2. 6H2O. (e) the number of millimoles of Cl2 in 25.0 ml of this solution. (f) ppm K+.

cium chloride per liter. Express the centration in terms of milliequivalents of calcium chloride (CaCl2-2H20-m.w 147) per liter. con- 27. How many milliequivalents/of potassium would be supplied daily by the usual dose (0.3 mL three times a day) of saturated potassium iodide solution? Saturated po- tassium iodide solution contains 100 g of potassium iodide per 100 mL.oluce 28. An intravenous solution calls for the addi- tion of 25 mEq of sodium bicarbonate. How many milli 4%

1. What weight of silver nitrate, AgNO3 (MM= 169.87 g/mol) is required to precipitate the chloride in 750 mg of 14.0% barium chloride, BaCl2 (MM = 208.33 g/mol)?Required to answer. 1 mole bacl2 and 2 moles Agno3

I’m stuck on this problem. Thank you