Show Work: 18+18=36 978 a. -247-26₁-418 6 ft 613306 буу 6хи au au Area of the Wall (84)² 8 ft Explain: дизай 18+24 Using Area of the Wall from 'a.' above, find the minimum length of wallpaper (rectangle) that is 2ft wide.

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Question
using area of the wall from ‘a.’ above, find the minimum length of the wallpaper(rectangle) that is 2ft wide.
have Show Work:
nere
b.
-247-26=418
18+18=36
ins
a.
6 ft
613306
6+4
au
Area of the Wall
6xu
au
8 ft
80D
6 ft
Explain:
дизай
18+24
Using Area of the Wall from 'a.' above, find the minimum
length of wallpaper (rectangle) that is 2ft wide.
Transcribed Image Text:have Show Work: nere b. -247-26=418 18+18=36 ins a. 6 ft 613306 6+4 au Area of the Wall 6xu au 8 ft 80D 6 ft Explain: дизай 18+24 Using Area of the Wall from 'a.' above, find the minimum length of wallpaper (rectangle) that is 2ft wide.
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