Show the content of the memory writing hexadecimal representation and using a table with 3 columns: the memory address, the contents of that memory address, and an explanation of what "the content (of that memory address) means". As a reference, here are the opcodes for RRR instructions: add 0, sub 1, mul 2, trap c. And here the opcodes for RX instructions: lea 0, load 1, store 2.

Show the content of the memory writing hexadecimal representation and using a table with 3 columns: the memory address, the contents of that memory address, and an explanation of what "the content (of that memory address) means". As a reference, here are the opcodes for RRR instructions: add 0, sub 1, mul 2, trap c. And here the opcodes for RX instructions: lea 0, load 1, store 2.

Name: (c) The following Sigma 16 program has been loaded into memory at add
Uploaded: 2024-03-20T06:51:23.000Z
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Description: (c) The following Sigma 16 program has been loaded into memory at address 0000:load R3,y[RO]load R4,x[RO]lea R5, 2[RO]sub R1,R4,R3mul R2,R1,R5store R2,w[RO]trap RO,RO,ROx data 10y data 12w data 0Show the content of the memory writing hexadecimal rep

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Which statement is correct for the memory segments in 8086 microprocessor? a. For Stack segment, the offset address can be a direct value. b. The offset address for program instructions is taken from SP register. c. Variables created in the Assembly program are stored in Data segment. d. Segment address for executing sub-routines is taken from ES register.
Make a distinction between the Code Segment, the Data Segment, and the Stack Segment. Then, for each segment, determine the registers combination that was utilized to address the data objects in each segment.
The condition known as orthogonality arises when the design of an instruction set includes a "backup" instruction for each and every other instruction that performs the same function. I would appreciate it if you could tell me whether or not it is accurate.
Take the following machine language instruction and fill in the translation of it in assembly language. The "alternative operand values" is how the operand may be expressed in assembly language either has hex (prefixed with Ox) or decimal (not prefixed with Ox). C00005 Binary IS: Mask: Instruction: [Select] [Select] [Select] [Select] Operand specifier: (four hex digits) Operand specifier: [Select] (alternative operand values) Addressing mode: [Select] (symbolic) Assembly: [Select] (instruction and operand)
Fetch Decode Execution Cycle Assignment Disassemble the following program (i.e., convert it back to assembly language) and determine what the program does. Refer to op-codes chart provided. (A Number Bit set to 1— Operand is a number) # Machine Code 0 001 1 000111 1 010 0 001101 2 001 1 000100 3 010 0 001110 4 001 0 001101 5 100 0 001110 6 010 0 001111 Op-code Mnemonic 001 LOAD 010 STORE 011 ADD 100 SUB 101 EQUAL 110 JUMP 111 HALT NB: Every stage must be present in a separate diagram with the description of the stage’s processes below. Extra marks would be allocated for neat and detailed work presented.
Consider the instruction ADD R1, M (R1 = R1 + [M]). M is the memory address of the operand. It is a two-word instruction – first word is the op-code and the second word is the address of the operand. Give the RTL description for the complete execution (including fetch phase) of the instruction.
Translate the following C code to MIPS assembly, assuming that the variables f, g, h, i, and j correspond to registers $50, $s1, $s2, $s3, and $54 respectively. Also, assume that the base addresses of arrays A and B are contained in $56 and $s7 respectively, and that each element of arrays A and B are 4-byte words: B[8] =A[i] + A[j]; Which of the following MIPS assembly code snippets correctly performs the above operation? sll $t1, $s3, 2; add $t1, $56, $t1; lw $12, 0($t1); sll $t1, $s4, 2; add $11, $s6, St1; lw $13, 0($t1); add $12, $12, $t3; sw $12, 32($s7) sll $t1, $s3, 2; add $11, $s6, $t1; lw $12, 0($t1); sll $t1, $s4, 2; add $11, $s6, $t1; lw $13, 0($t1); add $t4, $12, $t3; sll $15, $t0, 2; add $15, $s7, $15; sw $t4, 32($15) Iw $11,0($s3); Iw $12, 0($s4); add $13, $11, $12; sw $13, 32($s7) sll $t1, $s3, 2; lw $12, 0($t1); sll $t1, $s4, 2; lw $13, 0($t1); add $t4, $t2, $t3; sw $t4, 32($s7)
Q2. Interface 4 digit displays (each digit is a 7-segment display) to the 80386DX microprocessor (32 bit data bus and 32 bit address bus) using 8255 PPI. The 8255 should function at I/O addresses that start at 200H. Then write a program to initialize the 8255 and multiplex the 4 digit display where the data, in 7-segment code, that is to be displayed is stored at memory location 2000H: 0100H.
Which of the following statements is correct? 1) The 80/20 rule asserts that 80% of the instructions are executed and 20% of the instructions are produced. 2) The external bus in von Neumann architecture is exclusively used for data memory.
The code segment, the data segment, and the stack segment are all distinct. Then, determine the mix of registers utilized to address data objects in each segment.
In generall, computers think in terms of numbers (i.e. binary data). Thus, any operation performed in the computer must be done using either mathematical or logical operations. Given this inherit limitation of computers, what is the compare instruction actually doing when we, as assembly programmers, provide two numbers for it to "compare"? Furthermore, what assembly instruction is similar to the compare instruction? How are the two instructions different?
Explain the idea of a memory hierarchy in further detail. It is not quite obvious why the writers chose to format it in a pyramid format.