Show that X. dt f(x) J3 V1 + t4 is one-to-one. f'(x) = Since f'(x) O for all x, f is increasing v on (-0, o). Thus f is one-to-one. Find (f-1)'(0). (f-1)'(0) =
Show that X. dt f(x) J3 V1 + t4 is one-to-one. f'(x) = Since f'(x) O for all x, f is increasing v on (-0, o). Thus f is one-to-one. Find (f-1)'(0). (f-1)'(0) =
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![**Problem: Show that the function \( f(x) = \int_{3}^{x} \frac{dt}{\sqrt{1 + t^4}} \) is one-to-one.**
**Step 1: Find \( f'(x) \).**
\[ f'(x) = \]
**Observation:**
Since \( f'(x) \) \(\geq\) 0 for all \( x \), \( f \) is **increasing** on \((-\infty, \infty)\). Thus, \( f \) is one-to-one.
**Step 2: Find \((f^{-1})'(0)\).**
\[ (f^{-1})'(0) = \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdfec2b48-8f8e-4a41-b773-074a7cefe3d9%2F269932bd-49a0-44e8-99e4-261171130081%2F232fu_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem: Show that the function \( f(x) = \int_{3}^{x} \frac{dt}{\sqrt{1 + t^4}} \) is one-to-one.**
**Step 1: Find \( f'(x) \).**
\[ f'(x) = \]
**Observation:**
Since \( f'(x) \) \(\geq\) 0 for all \( x \), \( f \) is **increasing** on \((-\infty, \infty)\). Thus, \( f \) is one-to-one.
**Step 2: Find \((f^{-1})'(0)\).**
\[ (f^{-1})'(0) = \]
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