Show that x +x² + 1 is irreducible over Z2. Let a be a zero of x + x2 + 1 in an extension field of Z2. Show that x3 +x2 +1 factors into three linear factors in (Z2(@))[x] by actually finding this factorization. [Hint: Every element of Z2(a) is of the form ao + aja + a2a for a; = 0, 1. Divide x3 + x²+1 by x – a by long division. Show that the quotient also has a zero in Z2(a) by simply trving the eight nossible elements. Then complete the factorization.]

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Chapter2: Second-order Linear Odes
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Section 29 number 25
b. Finu a
E Of IR šuch that e² is algebraic of degree 5 over E.
25. a. Show that x+ x + 1 is irreducible over Z2.
b. Let a be a zero of x + x² +1 in an extension field of Z2. Show that x3+x² + 1 factors into three linear
factors in (Z2(a))[x] by actually finding this factorization. [Hint: Every element of Z2(a) is of the form
ao + aja + aza for a; = 0, 1.
Divide x + x² + 1 by x – a by long division. Show that the quotient also has a zero in Z2(@) by simply
trying the eight possible elements. Then complete the factorization.]
26. Let E be an extension field of Z2 and let a e E be algebraic of degree 3 over Z2. Classify the groups (Z2(@), +)
norom of finitely generated abelian groups. As usual, (Za(@)*
Transcribed Image Text:b. Finu a E Of IR šuch that e² is algebraic of degree 5 over E. 25. a. Show that x+ x + 1 is irreducible over Z2. b. Let a be a zero of x + x² +1 in an extension field of Z2. Show that x3+x² + 1 factors into three linear factors in (Z2(a))[x] by actually finding this factorization. [Hint: Every element of Z2(a) is of the form ao + aja + aza for a; = 0, 1. Divide x + x² + 1 by x – a by long division. Show that the quotient also has a zero in Z2(@) by simply trying the eight possible elements. Then complete the factorization.] 26. Let E be an extension field of Z2 and let a e E be algebraic of degree 3 over Z2. Classify the groups (Z2(@), +) norom of finitely generated abelian groups. As usual, (Za(@)*
Expert Solution
Step 1

(a)

The objective is to show that  is irreducible over .

Let .

If , then,

If , then,

So,  has no zeros over .

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