Show that the value of sin (x²) dx cannot possibly be 2. Choose the correct answer below. O A. The minimum value of sin (x²) on the interval [0, 1] is greater than 2. Therefore, 1 [sin (x²) dx> [2dx = 2. B. Since sin x is a transcendental function, the value of the integral of sin (x²) irrational number. over [0, 1] must be an OC. The maximum value of sin (x²) on the interval [0, 1] is less than 1. Therefore, 1 1 sin (x²) dxs [1dx=1<2. 0 OD. Since sin x has an average value of 0, the value of the integral of sin (x²) over [0, 1] must be close to 0.

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