Show that the transformation T defined by T(x₁, x₂) = (4x₁2x₂, X₁ +3, 5x₂) is not linear. 0 If T is a linear transformation, then T(0) = 0 -H 0 and T(cu + dv)=cT(u) +dT(v) for all vectors u, v in the domain of T and all scalars c, d. (Type a column vector.) Check if T(0) follows the correct property to be linear. T(0,0) = (4(0)-2(0), (0) +3, 5(0)) -0.00 = Substitute. Simplify.

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