Show that the transformation T defined by T(x₁, x₂) = (2x₁ - 3x2, X₁ +5, 5x₂) is not linear. 0 If T is a linear transformation, then T(0) = 0 and T(cu + dv) = cT(u) + dT(v) for all vectors u, v in the domain of T -11. 0 and all scalars c, d. (Type a column vector.) Check if T(0) follows the correct property to be linear. T(0,0) = (2(0)-3(0), (0) +5, 5(0)) = Substitute. Simplify.
Show that the transformation T defined by T(x₁, x₂) = (2x₁ - 3x2, X₁ +5, 5x₂) is not linear. 0 If T is a linear transformation, then T(0) = 0 and T(cu + dv) = cT(u) + dT(v) for all vectors u, v in the domain of T -11. 0 and all scalars c, d. (Type a column vector.) Check if T(0) follows the correct property to be linear. T(0,0) = (2(0)-3(0), (0) +5, 5(0)) = Substitute. Simplify.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question

Transcribed Image Text:Show that the transformation T defined by T(x₁, x₂) = (2x₁ - 3x₂, X₁ +5, 5x₂) is not linear.
If T is a linear transformation, then T(0) =
T(0,0) = (2(0)-3(0), (0)+5, 5(0))
-0.00
0
=
0
and all scalars c, d.
(Type a column vector.)
Check if T(0) follows the correct property to be linear.
and T(cu + dv)=cT(u)+dT(v) for all vectors u, v in the domain of T
Substitute.
Simplify.
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