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Show that the greedy algorithm for making change for n cents using quarters, dimes, nickels, and pennies has O(n) complexity measured in terms of comparisons needed. procedure change (c1, c2, . . . , Cr : coin denominations; n : a positive integer) for i := 1 to r di := 0 { di counts the coins of denomination c; used } while n > Ci d; := d; +1 { add a coin of denomination c; } n := n - ci { d; is the umber of coins of denomination c; in the change for i = 1,2, . . . , r}

Show that the greedy algorithm for making change for n cents using quarters, dimes, nickels, and pennies has O(n) complexity measured in terms of comparisons needed. procedure change (c1, c2, . . . , Cr : coin denominations; n : a positive integer) for i := 1 to r di := 0 { di counts the coins of denomination c; used } while n > Ci d; := d; +1 { add a coin of denomination c; } n := n - ci { d; is the umber of coins of denomination c; in the change for i = 1,2, . . . , r}

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Show that the greedy algorithm for making change for n cents using quarters, dimes, nickels, and pennies has O(n) complexity measured in terms of comparisons needed. procedure change (c1, c2, . . . , C, : coin denominations; n : a positive integer) for i := 1 to r di := 0 { di counts the coins of denomination c; used } while n > Ci d; := d; + 1 { add a coin of denomination c; } n := n – Ci { d; is the umber of coins of denomination c; in the change for i = 1,2, . . . , r}
Transcribed Image Text:Show that the greedy algorithm for making change for n cents using quarters, dimes, nickels, and pennies has O(n) complexity measured in terms of comparisons needed. procedure change (c1, c2, . . . , C, : coin denominations; n : a positive integer) for i := 1 to r di := 0 { di counts the coins of denomination c; used } while n > Ci d; := d; + 1 { add a coin of denomination c; } n := n – Ci { d; is the umber of coins of denomination c; in the change for i = 1,2, . . . , r}
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