Show that the given sequence is geometric. Then, find the common ratio and write out the first four terms.Sequence:\[\{c_n\} = \left\{\frac{4^{n-1}}{8}\right\}\]**Show that the sequence is geometric by demonstrating that the ratio of successive terms is a nonzero constant.**To determine the common ratio:\[\frac{c_n}{c_{n-1}} = \frac{\frac{4^{n-1}}{8}}{\frac{4^{n-2}}{8}} = \boxed{\phantom{\frac{}{}}}\](Type an exact answer in simplified form. Use integers or fractions for any numbers in the expression.)**Questions:**1. What is the value of the common ratio? - [ ] (Type an integer or a simplified fraction.)2. What is the value of the first term? - [ ] (Type an integer or a simplified fraction.)3. What is the value of the second term? - [ ] (Type an integer or a simplified fraction.)4. What is the value of the third term? - [ ] (Type an integer or a simplified fraction.)5. What is the value of the fourth term? - [ ] (Type an integer or a simplified fraction.)

Name: Show that the given sequence is geometric. Then, find the common rati
Uploaded: 2024-03-20T06:38:58.000Z
Channel: Bartleby
Description: Show that the given sequence is geometric. Then, find the common ratio and write out the first four terms.Sequence:\[\{c_n\} = \left\{\frac{4^{n-1}}{8}\right\}\]**Show that the sequence is geometric by demonstrating that the ratio of successive term