Show that the Frobenius mapping Φ: GF( pn) --> GF( pn), given bya --> ap, is a ring automorphism of order n (that is, Φn the identitymapping).
Show that the Frobenius mapping Φ: GF( pn) --> GF( pn), given bya --> ap, is a ring automorphism of order n (that is, Φn the identitymapping).
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Show that the Frobenius mapping Φ: GF( pn) --> GF( pn), given by
a --> ap, is a ring automorphism of order n (that is, Φn the identity
mapping).
Expert Solution
Step 1
Given:
The Frobenius mapping is given by: .
We have to show that is a ring automorphism of order n.
Step 2
We know, Finite field is perfect.
is surjective.
Also, since is a map from to .
Therefore, .
Hence is injective.
And thus is a one-to-one mapping from to .
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