Show that the dispersion relation for the lattice vibrations of a chain of identical masses M, in which each is connected to its first and second nearest neighbours by springs of spring constants K and K, respectively, is Mo = 2K[1- cos(ka)]+2K,[1-cos(2ka)] where a is the equilibrium spacing. Show that: this dispersion relation reduces to that for sound waves in the long-wavelength limit (ensure that the velocity corresponds to that predicted by the elastic modulus of the crystal); the group velocity vanishes at k = t7/a; and o is periodic in k with period 2/a.
Show that the dispersion relation for the lattice vibrations of a chain of identical masses M, in which each is connected to its first and second nearest neighbours by springs of spring constants K and K, respectively, is Mo = 2K[1- cos(ka)]+2K,[1-cos(2ka)] where a is the equilibrium spacing. Show that: this dispersion relation reduces to that for sound waves in the long-wavelength limit (ensure that the velocity corresponds to that predicted by the elastic modulus of the crystal); the group velocity vanishes at k = t7/a; and o is periodic in k with period 2/a.
Related questions
Question
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 3 steps