- Show that S¹ = {(x, y) = R²|x² + y² = 1} and D² = {(x, y) = R²|x² + y² ≤ 1} have the same cardinality.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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5. Show that S¹
same cardinality.
{(x, y) = R²|x² + y² = 1} and D² = {(x, y) = R²|x² + y² ≤ 1} have the
Transcribed Image Text:5. Show that S¹ same cardinality. {(x, y) = R²|x² + y² = 1} and D² = {(x, y) = R²|x² + y² ≤ 1} have the
Expert Solution
Step 1: Define function

To show that the unit circle S to the power of 1 and the closed unit disk D squared have the same cardinality, establish a bijection between the two sets.

Define a function f colon S to the power of 1 not stretchy rightwards arrow D squared as follows:

f not stretchy left parenthesis x comma y not stretchy right parenthesis equals not stretchy left parenthesis x comma y not stretchy right parenthesis

In other words, f takes a point not stretchy left parenthesis x comma y not stretchy right parenthesis on the unit circle S to the power of 1 and maps it to the same point not stretchy left parenthesis x comma y not stretchy right parenthesis in the closed unit disk D squared. This function is well-defined because every point on S to the power of 1 is also a point in D squared since S to the power of 1 is a subset of D squared.


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