Show that Planck's radiation law is given by: 8лhy³ c³ u(v)dv= 1 exp(hv/kT) -1 -dv
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A: Given: g =e2f4-h2ie = 7.83±0.04f = 0.204±0.007h = 14.14±0.05i = 3.99±0.03
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A: side of ceramics cube = 4.1 cm = 0.041 mpower ,P=510 W and e=1
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A: If you have any help please let me know in comment box.
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