Show that if x is in both W and W-, then x = 0.

Q: 2. LetG = (Z12,) & H == {4,8,0}. Then [G:H]=3. *True *False

A:

Q: and -5 Compute ū - v. 2

A: Given    Formula :

Q: Are u sure its not 1

A: It is given that a=0 and b=1.

Q: 6. Let F = (-6, 5)U{-10, 10} U [7, 11). Find max F, min F, sup F, and inf F if they exist.

A:

Q: Let R = [1, 2] × [1, 2]. Compute ye*"dA. R

A:

Q: Find the value of a for which U = a 1 10 is in the set 0 -1 3 0 H = span 5 3 -1 2 -2 -2 a =

A: The value of a=-7 .Explanation:Step 1: Step 2: Step 3: Step 4:

Q: Let U= {1, 7, 2, 12, 5, 10, 20, 18} A = {1, 20, 18} C = {7, 2, 12, 5, 10} Find A U C'.

A:

Q: Let à =. Find |ā|.

A:

Q: Prove that u × 0 = 0 × u = 0.

A:

Q: u = [2, 6, –5] and v= [-3,–1,6] %3D A · A + (A + ng-) · (A x n)

A:

Q: 10.

A:

Q: Let y = Ա 4 + DIS 5 Ա and u = x³ = x³ - 2x.

A:

Q: Let u = = (–3, 3, 5) and v = (−6, −4, −7). Compute the following: ū X x v = v × x ū x ū ū=

A: Please note that as per bartleby guidelines, we need to answer only the first three sub-parts.Kindly…

Q: 4. Which relation between x and u yields 16+x² = 4/1+u?

A: Given:

Q: Let v = (5, 1, 2) and w = (4, –3, 6). Find each of the following: v+ w, v– 3w, || v||, || v – w ||

A: Solution: The objective is to find the required values

Q: Show that the set { 159 is linearly independent

A:

Q: Show that if AB={0}, then P(A)≤P(B).

A: Given that

Q: |

A: vector q is not in the span of vectors.  p1,p2and p3. complete explanation is given…

Q: Suppose X~N(112,16), and Z~N(0,1). Then x = 112, is equivalent to z = ______.

A: