Show that if the production function is concave, the cost function is convex (in y).

ENGR.ECONOMIC ANALYSIS
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Chapter1: Making Economics Decisions
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Show that if the production function is concave, the cost function is convex
(in y).
Transcribed Image Text:Show that if the production function is concave, the cost function is convex (in y).
1. The Cobb-Douglas production function is f(x1,x2) = Axx. To get the Lagrange multiplier of the
cost minimization problem, you will need to solve the following cost minimization problem:
min w,x1 + W2*2
X1,X220
subject to f(x1, x2) = Ax*x 2y
You will set up the Lagrangian, take first-order conditions, and use them to solve for x, (W, W2, y) and
x2 (W1, W2, y). Then you can substitute these values back into one of your first-order conditions to solve
for your Lagrange multiplier.
To show that this is equal to the derivative of the cost function, you will need to get the cost function by
substituting your calculations for x, (w, W2, y) and x2 (W1, Wz2, y) into w1x1 + W1x2. This will give you
the cost function, c(w1, W2, y). You can then take its derivative with respect to output, y, and note that
it is equal to your Lagrange multiplier.
2. Focus on just getting the cost function and the conditional demands for inputs. You do not need to
solve an additional cost minimization problem if you notice that this is similar to questions 1, but with
additional fixed costs. That is, your cost functions will just be the cost function from #1 plus
w,ł, + wzł2, and your conditional demands for inputs will be the same as in #1 but with +x, for
x1 (W1, W2. y) and +žz for x2(W1,W2, y).
Helping material
3. I did not write the problem sets (or quizzes, tests, lecture notes, etc.), so I don't have the
ability/authority to change this question, but I find it very confusing and unclear as to what it is asking
for. Feel free to skip this problem.
4. You can get the conditional demands for inputs and the cost function in the same manner as in
problem 1, except now with the CES production function.
5. It may be helpful to use the equation s'(wy) _ dinc(wy)
and the fact that xg = c'(w,y). Even though
c(w.y)
this one says "lots of algebra", it really shouldn't be nearly as much as some of the previous problems.
6. same process as #5
Transcribed Image Text:1. The Cobb-Douglas production function is f(x1,x2) = Axx. To get the Lagrange multiplier of the cost minimization problem, you will need to solve the following cost minimization problem: min w,x1 + W2*2 X1,X220 subject to f(x1, x2) = Ax*x 2y You will set up the Lagrangian, take first-order conditions, and use them to solve for x, (W, W2, y) and x2 (W1, W2, y). Then you can substitute these values back into one of your first-order conditions to solve for your Lagrange multiplier. To show that this is equal to the derivative of the cost function, you will need to get the cost function by substituting your calculations for x, (w, W2, y) and x2 (W1, Wz2, y) into w1x1 + W1x2. This will give you the cost function, c(w1, W2, y). You can then take its derivative with respect to output, y, and note that it is equal to your Lagrange multiplier. 2. Focus on just getting the cost function and the conditional demands for inputs. You do not need to solve an additional cost minimization problem if you notice that this is similar to questions 1, but with additional fixed costs. That is, your cost functions will just be the cost function from #1 plus w,ł, + wzł2, and your conditional demands for inputs will be the same as in #1 but with +x, for x1 (W1, W2. y) and +žz for x2(W1,W2, y). Helping material 3. I did not write the problem sets (or quizzes, tests, lecture notes, etc.), so I don't have the ability/authority to change this question, but I find it very confusing and unclear as to what it is asking for. Feel free to skip this problem. 4. You can get the conditional demands for inputs and the cost function in the same manner as in problem 1, except now with the CES production function. 5. It may be helpful to use the equation s'(wy) _ dinc(wy) and the fact that xg = c'(w,y). Even though c(w.y) this one says "lots of algebra", it really shouldn't be nearly as much as some of the previous problems. 6. same process as #5
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